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Sagot :
To determine if the point [tex]\((2,3)\)[/tex] is a solution to the system of linear equations:
[tex]\[ \begin{array}{l} y = 2x - 1 \\ y = x + 1 \end{array} \][/tex]
we need to check if substituting [tex]\(x = 2\)[/tex] and [tex]\(y = 3\)[/tex] into both equations makes them true.
1. Check the first equation: [tex]\(y = 2x - 1\)[/tex]
Substitute [tex]\(x = 2\)[/tex] and [tex]\(y = 3\)[/tex]:
[tex]\[ 3 = 2(2) - 1 \][/tex]
Simplify the right side:
[tex]\[ 3 = 4 - 1 \][/tex]
[tex]\[ 3 = 3 \][/tex]
This equation is satisfied.
2. Check the second equation: [tex]\(y = x + 1\)[/tex]
Substitute [tex]\(x = 2\)[/tex] and [tex]\(y = 3\)[/tex]:
[tex]\[ 3 = 2 + 1 \][/tex]
Simplify the right side:
[tex]\[ 3 = 3 \][/tex]
This equation is also satisfied.
Since both equations are satisfied when [tex]\(x = 2\)[/tex] and [tex]\(y = 3\)[/tex], the point [tex]\((2,3)\)[/tex] satisfies the system of linear equations.
Therefore, the statement:
[tex]$(2,3)$[/tex] is a solution to the following system of linear equations:
[tex]\[ \begin{array}{l} y = 2 x - 1 \\ y = x + 1 \end{array} \][/tex]
is True.
[tex]\[ \begin{array}{l} y = 2x - 1 \\ y = x + 1 \end{array} \][/tex]
we need to check if substituting [tex]\(x = 2\)[/tex] and [tex]\(y = 3\)[/tex] into both equations makes them true.
1. Check the first equation: [tex]\(y = 2x - 1\)[/tex]
Substitute [tex]\(x = 2\)[/tex] and [tex]\(y = 3\)[/tex]:
[tex]\[ 3 = 2(2) - 1 \][/tex]
Simplify the right side:
[tex]\[ 3 = 4 - 1 \][/tex]
[tex]\[ 3 = 3 \][/tex]
This equation is satisfied.
2. Check the second equation: [tex]\(y = x + 1\)[/tex]
Substitute [tex]\(x = 2\)[/tex] and [tex]\(y = 3\)[/tex]:
[tex]\[ 3 = 2 + 1 \][/tex]
Simplify the right side:
[tex]\[ 3 = 3 \][/tex]
This equation is also satisfied.
Since both equations are satisfied when [tex]\(x = 2\)[/tex] and [tex]\(y = 3\)[/tex], the point [tex]\((2,3)\)[/tex] satisfies the system of linear equations.
Therefore, the statement:
[tex]$(2,3)$[/tex] is a solution to the following system of linear equations:
[tex]\[ \begin{array}{l} y = 2 x - 1 \\ y = x + 1 \end{array} \][/tex]
is True.
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