Connect with a global community of knowledgeable individuals on IDNLearn.com. Get comprehensive answers to all your questions from our network of experienced experts.
Sagot :
To solve this problem, we need to find the kinetic energy of the roller coaster car at the top and bottom of the hill.
### Step-by-Step Solution:
1. Determine the given values:
- Mass of the roller coaster car, [tex]\( m \)[/tex] = 100 kg
- Speed at the top of the hill, [tex]\( v_{top} \)[/tex] = 3 m/s
- At the bottom of the hill, the speed doubles, so [tex]\( v_{bottom} = 2 \times v_{top} = 2 \times 3 \)[/tex] m/s = 6 m/s
2. Calculate the kinetic energy at the top of the hill:
The formula for kinetic energy is given by:
[tex]\[ KE = \frac{1}{2} m v^2 \][/tex]
Plugging in the values for the top of the hill:
[tex]\[ KE_{top} = \frac{1}{2} \times 100 \, \text{kg} \times (3 \, \text{m/s})^2 \][/tex]
[tex]\[ KE_{top} = \frac{1}{2} \times 100 \times 9 \][/tex]
[tex]\[ KE_{top} = 450 \, \text{Joules} \][/tex]
3. Calculate the kinetic energy at the bottom of the hill:
Using the same formula and plugging in the values for the bottom of the hill:
[tex]\[ KE_{bottom} = \frac{1}{2} \times 100 \, \text{kg} \times (6 \, \text{m/s})^2 \][/tex]
[tex]\[ KE_{bottom} = \frac{1}{2} \times 100 \times 36 \][/tex]
[tex]\[ KE_{bottom} = 1800 \, \text{Joules} \][/tex]
4. Analyze the relationship between the kinetic energies:
To determine how the kinetic energy at the bottom compares to the top, we divide the kinetic energy at the bottom by the kinetic energy at the top:
[tex]\[ \frac{KE_{bottom}}{KE_{top}} = \frac{1800}{450} = 4 \][/tex]
Therefore, the kinetic energy at the bottom is 4 times the kinetic energy at the top.
### Summary:
- The car's kinetic energy at the bottom is 4 times its kinetic energy at the top.
- The car has 1800 Joules of kinetic energy at the bottom of the hill.
Thus, the correct selections for the drop-down menus are:
1. The car's kinetic energy at the bottom is 4 times its kinetic energy at the top.
2. The car has 1800 Joules of kinetic energy at the bottom of the hill.
### Step-by-Step Solution:
1. Determine the given values:
- Mass of the roller coaster car, [tex]\( m \)[/tex] = 100 kg
- Speed at the top of the hill, [tex]\( v_{top} \)[/tex] = 3 m/s
- At the bottom of the hill, the speed doubles, so [tex]\( v_{bottom} = 2 \times v_{top} = 2 \times 3 \)[/tex] m/s = 6 m/s
2. Calculate the kinetic energy at the top of the hill:
The formula for kinetic energy is given by:
[tex]\[ KE = \frac{1}{2} m v^2 \][/tex]
Plugging in the values for the top of the hill:
[tex]\[ KE_{top} = \frac{1}{2} \times 100 \, \text{kg} \times (3 \, \text{m/s})^2 \][/tex]
[tex]\[ KE_{top} = \frac{1}{2} \times 100 \times 9 \][/tex]
[tex]\[ KE_{top} = 450 \, \text{Joules} \][/tex]
3. Calculate the kinetic energy at the bottom of the hill:
Using the same formula and plugging in the values for the bottom of the hill:
[tex]\[ KE_{bottom} = \frac{1}{2} \times 100 \, \text{kg} \times (6 \, \text{m/s})^2 \][/tex]
[tex]\[ KE_{bottom} = \frac{1}{2} \times 100 \times 36 \][/tex]
[tex]\[ KE_{bottom} = 1800 \, \text{Joules} \][/tex]
4. Analyze the relationship between the kinetic energies:
To determine how the kinetic energy at the bottom compares to the top, we divide the kinetic energy at the bottom by the kinetic energy at the top:
[tex]\[ \frac{KE_{bottom}}{KE_{top}} = \frac{1800}{450} = 4 \][/tex]
Therefore, the kinetic energy at the bottom is 4 times the kinetic energy at the top.
### Summary:
- The car's kinetic energy at the bottom is 4 times its kinetic energy at the top.
- The car has 1800 Joules of kinetic energy at the bottom of the hill.
Thus, the correct selections for the drop-down menus are:
1. The car's kinetic energy at the bottom is 4 times its kinetic energy at the top.
2. The car has 1800 Joules of kinetic energy at the bottom of the hill.
Your engagement is important to us. Keep sharing your knowledge and experiences. Let's create a learning environment that is both enjoyable and beneficial. For precise answers, trust IDNLearn.com. Thank you for visiting, and we look forward to helping you again soon.