IDNLearn.com helps you find the answers you need quickly and efficiently. Our platform is designed to provide trustworthy and thorough answers to any questions you may have.
Sagot :
To determine how many moles of lithium hydroxide (LiOH) are required to react with 20 moles of carbon dioxide (CO₂), we can use the stoichiometric relationship given in the balanced chemical equation:
[tex]\[ CO_2(g) + 2 LiOH(s) \rightarrow Li_2CO_3(s) + H_2O(l) \][/tex]
From the balanced equation, we see that 1 mole of CO₂ reacts with 2 moles of LiOH. This gives us the stoichiometric ratio:
[tex]\[ 1 \text{ mole of } CO_2 : 2 \text{ moles of } LiOH \][/tex]
Now, let's determine how many moles of LiOH are needed to react with 20 moles of CO₂.
Step-by-step procedure:
1. Identify the given quantity: We know that we have 20 moles of CO₂.
2. Use the stoichiometric ratio to find the required amount of LiOH:
[tex]\[ \text{Moles of LiOH} = 2 \times \text{Moles of CO₂} \][/tex]
3. Substitute the given quantity (20 moles of CO₂) into the equation:
[tex]\[ \text{Moles of LiOH} = 2 \times 20 \text{ moles of CO₂} \][/tex]
4. Calculate the result:
[tex]\[ \text{Moles of LiOH} = 40 \text{ moles of LiOH} \][/tex]
Therefore, 40 moles of lithium hydroxide (LiOH) are required to react with 20 moles of carbon dioxide (CO₂), which is the average amount exhaled by a person each day.
Based on our calculation, the correct answer is:
- 40 moles
[tex]\[ CO_2(g) + 2 LiOH(s) \rightarrow Li_2CO_3(s) + H_2O(l) \][/tex]
From the balanced equation, we see that 1 mole of CO₂ reacts with 2 moles of LiOH. This gives us the stoichiometric ratio:
[tex]\[ 1 \text{ mole of } CO_2 : 2 \text{ moles of } LiOH \][/tex]
Now, let's determine how many moles of LiOH are needed to react with 20 moles of CO₂.
Step-by-step procedure:
1. Identify the given quantity: We know that we have 20 moles of CO₂.
2. Use the stoichiometric ratio to find the required amount of LiOH:
[tex]\[ \text{Moles of LiOH} = 2 \times \text{Moles of CO₂} \][/tex]
3. Substitute the given quantity (20 moles of CO₂) into the equation:
[tex]\[ \text{Moles of LiOH} = 2 \times 20 \text{ moles of CO₂} \][/tex]
4. Calculate the result:
[tex]\[ \text{Moles of LiOH} = 40 \text{ moles of LiOH} \][/tex]
Therefore, 40 moles of lithium hydroxide (LiOH) are required to react with 20 moles of carbon dioxide (CO₂), which is the average amount exhaled by a person each day.
Based on our calculation, the correct answer is:
- 40 moles
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Thank you for choosing IDNLearn.com. We’re committed to providing accurate answers, so visit us again soon.