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To solve the subtraction problem [tex]\(36 - 0.0048\)[/tex], let's carefully go through the steps together:
1. Understand the problem: We need to subtract a small value, [tex]\(0.0048\)[/tex], from a larger whole number, [tex]\(36\)[/tex].
2. Align the decimal points: When performing the subtraction, it is important to align the decimal points correctly. However, since [tex]\(36\)[/tex] can be written as [tex]\(36.0000\)[/tex] (with implied zeros in the decimal places), we can align it as follows:
[tex]\[ 36.0000 - 0.0048 \][/tex]
3. Subtract digit by digit: Starting from the rightmost digit (the thousandths place), we can perform the subtraction step-by-step:
- Thousandths place: [tex]\(0 - 8\)[/tex]. Since [tex]\(0\)[/tex] is less than [tex]\(8\)[/tex], we need to borrow from the next significant digit.
- We borrow from the tenths place, making the calculation appear as [tex]\(1000 - 8 = 992\)[/tex]. Keeping the carried over 1 in mind, the correct digit becomes [tex]\(2\)[/tex].
Following similar borrowing and subtracting steps, we can determine that:
[tex]\[ \begin{array}{cccccc} & 3 & 6 & . & 0 & 0 & 0 & 0 \\ - & & 0 & . & 0 & 0 & 4 & 8 \\ \hline & 3 & 5 & . & 9 & 9 & 5 & 2 \\ \end{array} \][/tex]
4. Confirm and write the final result: After performing all the steps of subtraction, we get the final result:
[tex]\[ 36 - 0.0048 = 35.9952 \][/tex]
Therefore, the correct answer to the question [tex]\(36 - 0.0048\)[/tex] is:
[tex]\[ \boxed{35.9952} \][/tex]
So, the correct option is:
[tex]\[ \text{c. 35.9952} \][/tex]
1. Understand the problem: We need to subtract a small value, [tex]\(0.0048\)[/tex], from a larger whole number, [tex]\(36\)[/tex].
2. Align the decimal points: When performing the subtraction, it is important to align the decimal points correctly. However, since [tex]\(36\)[/tex] can be written as [tex]\(36.0000\)[/tex] (with implied zeros in the decimal places), we can align it as follows:
[tex]\[ 36.0000 - 0.0048 \][/tex]
3. Subtract digit by digit: Starting from the rightmost digit (the thousandths place), we can perform the subtraction step-by-step:
- Thousandths place: [tex]\(0 - 8\)[/tex]. Since [tex]\(0\)[/tex] is less than [tex]\(8\)[/tex], we need to borrow from the next significant digit.
- We borrow from the tenths place, making the calculation appear as [tex]\(1000 - 8 = 992\)[/tex]. Keeping the carried over 1 in mind, the correct digit becomes [tex]\(2\)[/tex].
Following similar borrowing and subtracting steps, we can determine that:
[tex]\[ \begin{array}{cccccc} & 3 & 6 & . & 0 & 0 & 0 & 0 \\ - & & 0 & . & 0 & 0 & 4 & 8 \\ \hline & 3 & 5 & . & 9 & 9 & 5 & 2 \\ \end{array} \][/tex]
4. Confirm and write the final result: After performing all the steps of subtraction, we get the final result:
[tex]\[ 36 - 0.0048 = 35.9952 \][/tex]
Therefore, the correct answer to the question [tex]\(36 - 0.0048\)[/tex] is:
[tex]\[ \boxed{35.9952} \][/tex]
So, the correct option is:
[tex]\[ \text{c. 35.9952} \][/tex]
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