Join the IDNLearn.com community and start getting the answers you need today. Join our community to receive prompt, thorough responses from knowledgeable experts.
Sagot :
To find the missing values in the trigonometric identities, let's use the property that relates the sine and cosine of complementary angles. This property states that [tex]\(\sin(\theta) = \cos(90^\circ - \theta)\)[/tex] and [tex]\(\cos(\theta) = \sin(90^\circ - \theta)\)[/tex].
1. First expression: [tex]\(\sin(28^\circ) = \cos(\square)\)[/tex]
To find the angle for this relationship, we use the property [tex]\(\sin(\theta) = \cos(90^\circ - \theta)\)[/tex]:
[tex]\[ \sin(28^\circ) = \cos(90^\circ - 28^\circ) \][/tex]
Calculating [tex]\(90^\circ - 28^\circ\)[/tex]:
[tex]\[ 90^\circ - 28^\circ = 62^\circ \][/tex]
So, [tex]\(\sin(28^\circ) = \cos(62^\circ)\)[/tex].
Therefore, [tex]\(\square = 62^\circ\)[/tex].
2. Second expression: [tex]\(\cos(33^\circ) = \sin(\square)\)[/tex]
Here, we use the property [tex]\(\cos(\theta) = \sin(90^\circ - \theta)\)[/tex]:
[tex]\[ \cos(33^\circ) = \sin(90^\circ - 33^\circ) \][/tex]
Calculating [tex]\(90^\circ - 33^\circ\)[/tex]:
[tex]\[ 90^\circ - 33^\circ = 57^\circ \][/tex]
So, [tex]\(\cos(33^\circ) = \sin(57^\circ)\)[/tex].
Therefore, [tex]\(\square = 57^\circ\)[/tex].
3. Third expression: [tex]\(\cos(31^\circ) = \sin(\square)\)[/tex]
Again, using the property [tex]\(\cos(\theta) = \sin(90^\circ - \theta)\)[/tex]:
[tex]\[ \cos(31^\circ) = \sin(90^\circ - 31^\circ) \][/tex]
Calculating [tex]\(90^\circ - 31^\circ\)[/tex]:
[tex]\[ 90^\circ - 31^\circ = 59^\circ \][/tex]
So, [tex]\(\cos(31^\circ) = \sin(59^\circ)\)[/tex].
Therefore, [tex]\(\square = 59^\circ\)[/tex].
4. Fourth expression: [tex]\(\cos(90^\circ - \theta) = \sin(\theta)\)[/tex]
By definition, we know that this relationship is always true without additional computation.
To summarize, we have found the following identities:
- [tex]\(\sin(28^\circ) = \cos(62^\circ)\)[/tex]
- [tex]\(\cos(33^\circ) = \sin(57^\circ)\)[/tex]
- [tex]\(\cos(31^\circ) = \sin(59^\circ)\)[/tex]
- [tex]\(\cos(90^\circ - \theta) = \sin(\theta)\)[/tex]
Thus, the completed list of expressions is:
[tex]\[ \begin{array}{l} \sin(28^\circ) = \cos(62^\circ) \\ \cos(33^\circ) = \sin(57^\circ) \\ \cos(31^\circ) = \sin(59^\circ) \\ \cos(90^\circ - \theta) = \sin(\theta) \end{array} \][/tex]
1. First expression: [tex]\(\sin(28^\circ) = \cos(\square)\)[/tex]
To find the angle for this relationship, we use the property [tex]\(\sin(\theta) = \cos(90^\circ - \theta)\)[/tex]:
[tex]\[ \sin(28^\circ) = \cos(90^\circ - 28^\circ) \][/tex]
Calculating [tex]\(90^\circ - 28^\circ\)[/tex]:
[tex]\[ 90^\circ - 28^\circ = 62^\circ \][/tex]
So, [tex]\(\sin(28^\circ) = \cos(62^\circ)\)[/tex].
Therefore, [tex]\(\square = 62^\circ\)[/tex].
2. Second expression: [tex]\(\cos(33^\circ) = \sin(\square)\)[/tex]
Here, we use the property [tex]\(\cos(\theta) = \sin(90^\circ - \theta)\)[/tex]:
[tex]\[ \cos(33^\circ) = \sin(90^\circ - 33^\circ) \][/tex]
Calculating [tex]\(90^\circ - 33^\circ\)[/tex]:
[tex]\[ 90^\circ - 33^\circ = 57^\circ \][/tex]
So, [tex]\(\cos(33^\circ) = \sin(57^\circ)\)[/tex].
Therefore, [tex]\(\square = 57^\circ\)[/tex].
3. Third expression: [tex]\(\cos(31^\circ) = \sin(\square)\)[/tex]
Again, using the property [tex]\(\cos(\theta) = \sin(90^\circ - \theta)\)[/tex]:
[tex]\[ \cos(31^\circ) = \sin(90^\circ - 31^\circ) \][/tex]
Calculating [tex]\(90^\circ - 31^\circ\)[/tex]:
[tex]\[ 90^\circ - 31^\circ = 59^\circ \][/tex]
So, [tex]\(\cos(31^\circ) = \sin(59^\circ)\)[/tex].
Therefore, [tex]\(\square = 59^\circ\)[/tex].
4. Fourth expression: [tex]\(\cos(90^\circ - \theta) = \sin(\theta)\)[/tex]
By definition, we know that this relationship is always true without additional computation.
To summarize, we have found the following identities:
- [tex]\(\sin(28^\circ) = \cos(62^\circ)\)[/tex]
- [tex]\(\cos(33^\circ) = \sin(57^\circ)\)[/tex]
- [tex]\(\cos(31^\circ) = \sin(59^\circ)\)[/tex]
- [tex]\(\cos(90^\circ - \theta) = \sin(\theta)\)[/tex]
Thus, the completed list of expressions is:
[tex]\[ \begin{array}{l} \sin(28^\circ) = \cos(62^\circ) \\ \cos(33^\circ) = \sin(57^\circ) \\ \cos(31^\circ) = \sin(59^\circ) \\ \cos(90^\circ - \theta) = \sin(\theta) \end{array} \][/tex]
We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. IDNLearn.com is your source for precise answers. Thank you for visiting, and we look forward to helping you again soon.