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Answer:
[tex]\textsf{A)}\quad \sqrt{4 \cdot 15}[/tex]
Step-by-step explanation:
To rewrite the radicand of [tex]\sqrt{60}[/tex] as two factors, one of which is a perfect square, we start by factoring 60 into its prime factors:
[tex]60=2 \times 2 \times 3 \times 5\\\\60 = 2^2 \times 3 \times 5[/tex]
A perfect square is a number that can be expressed as the product of an integer multiplied by itself. Therefore, the factor 2² = 4 is a perfect square. So we can rewrite 60 as:
[tex]60 = 4 \times 15[/tex]
Therefore, the radicand of [tex]\sqrt{60}[/tex] rewritten as two factors is:
[tex]\LARGE\boxed{\boxed{\sqrt{4 \cdot 15}}}[/tex]