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If a heterozygous male with the genotype [tex]Ww[/tex] is mated with a homozygous recessive female of genotype [tex]ww[/tex], there is a [tex]$\square$[/tex] chance that the offspring will be heterozygous.
[tex]\[
\begin{tabular}{|c|c|c|}
\hline & W & w \\
\hline w & Ww & ww \\
\hline w & Ww & ww \\
\hline
\end{tabular}
\][/tex]

If the heterozygous [tex]Ww[/tex] is crossed with a homozygous dominant [tex]WW[/tex], then the probability of having a homozygous recessive offspring is
[tex]\[
\begin{tabular}{|c|c|c|}
\hline & W & W \\
\hline W & WW & WW \\
\hline w & Ww & Ww \\
\hline
\end{tabular}
\][/tex]

Sagot :

GinnyAnsweridn
Let's approach this problem in two steps.

### Step 1: Heterozygous Male (Ww) and Homozygous Recessive Female (ww)

A heterozygous genotype means an individual has one dominant allele (W) and one recessive allele (w). A homozygous recessive genotype means an individual has two recessive alleles (ww).

When a heterozygous male (Ww) is mated with a homozygous recessive female (ww), the possible offspring genotypes are represented by the following Punnett square:

[tex]\[ \begin{array}{|c|c|c|} \hline & W & w \\ \hline w & Ww & ww \\ \hline w & Ww & ww \\ \hline \end{array} \][/tex]

From the Punnett square, the offspring genotypes are:
- 2 Ww (heterozygous)
- 2 ww (homozygous recessive)

So, the chance that the offspring will be heterozygous (Ww) is [tex]$2/4$[/tex] or [tex]$50\%$[/tex].

### Step 2: Crossing Heterozygous Ww with Homozygous Dominant WW

Next, we cross a heterozygous individual (Ww) with a homozygous dominant individual (WW):

[tex]\[ \begin{array}{|c|c|c|} \hline & W & W \\ \hline W & WW & WW \\ \hline w & Ww & Ww \\ \hline \end{array} \][/tex]

The possible offspring genotypes are:
- 2 WW (homozygous dominant)
- 2 Ww (heterozygous)

There are no ww (homozygous recessive) offspring in this cross.

So, the probability of having a homozygous recessive offspring (ww) is [tex]$0\%$[/tex].

### Final Answer

Based on this analysis:

1. There is a 50% chance that the offspring from a cross between a heterozygous male [tex]\(Ww\)[/tex] and a homozygous recessive female [tex]\(ww\)[/tex] will be heterozygous.
2. There is a 0% probability of having a homozygous recessive offspring (ww) when a heterozygous ([tex]\(Ww\)[/tex]) is crossed with a homozygous dominant ([tex]\(WW\)[/tex]).

The correct answers to fill in the drop-down menus are:

- For the first sentence: "50%"
- For the second sentence: "0%"
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