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For the given equation, what is the step to clear the fractions and what is the result?

[tex]\[\frac{2 y}{3} - \frac{1}{6} = \frac{7}{2}\][/tex]

A. Multiply both sides by 6 to get [tex]\(2y - 1 = 7\)[/tex].

B. Multiply both sides by 18 to get [tex]\(12y - 3 = 63\)[/tex].

C. Multiply both sides by 12 to get [tex]\(4y - 2 = 42\)[/tex].

D. Multiply both sides by 6 to get [tex]\(4y - 1 = 21\)[/tex].


Sagot :

To clear the fractions in the given equation and simplify it, follow these steps:

1. Start with the given equation:
[tex]\[ \frac{2y}{3} - \frac{1}{6} = \frac{7}{2} \][/tex]

2. Identify a common multiple for the denominators 3, 6, and 2. The least common multiple (LCM) of these denominators is 6.

3. Multiply every term in the equation by 6 to clear the fractions:
[tex]\[ 6 \left(\frac{2y}{3}\right) - 6 \left(\frac{1}{6}\right) = 6 \left(\frac{7}{2}\right) \][/tex]

4. Simplify each term:
[tex]\[ \left(6 \div 3\right) \cdot 2y - \left(6 \div 6\right) \cdot 1 = (6 \div 2) \cdot 7 \][/tex]
This reduces to:
[tex]\[ 2 \cdot 2y - 1 = 3 \cdot 7 \][/tex]
Further simplification gives us:
[tex]\[ 4y - 1 = 21 \][/tex]

Therefore, the step to clear the fractions is to multiply both sides of the equation by 6, and the resulting equation is:
[tex]\[ 4y - 1 = 21 \][/tex]