When a heterozygous male with the genotype Ww is mated with a homozygous recessive female of genotype ww, we use a Punnett square to determine the possible genotypes of the offspring. Here is the Punnett square:
\begin{tabular}{|c|c|c|}
\hline & [tex]$W$[/tex] & [tex]$w$[/tex] \\
\hline[tex]$w$[/tex] & [tex]$W w$[/tex] & [tex]$w w$[/tex] \\
\hline[tex]$w$[/tex] & [tex]$W w$[/tex] & [tex]$w w$[/tex] \\
\hline
\end{tabular}
From this Punnett square, we can see that there are 2 Ww (heterozygous) offspring out of a total of 4 possible offspring. Therefore, the probability of heterozygous offspring is:
[tex]\[
\frac{2}{4} = 0.5
\][/tex]
Next, if we cross a heterozygous genotype (Ww) with a homozygous dominant genotype (WW), we use another Punnett square:
\begin{tabular}{|c|c|c|}
\hline & [tex]$W$[/tex] & [tex]$w$[/tex] \\
\hline[tex]$W$[/tex] & [tex]$W W$[/tex] & [tex]$W w$[/tex] \\
\hline[tex]$W$[/tex] & [tex]$W W$[/tex] & [tex]$W w$[/tex] \\
\hline
\end{tabular}
In this case, we can see that there are no homozygous recessive (ww) offspring because all the possible offspring types are either WW or Ww. Thus, the probability of homozygous recessive offspring is:
[tex]\[
\frac{0}{4} = 0.0
\][/tex]
So, the answers are:
1. There is a 0.5 chance that the offspring will be heterozygous (Ww).
2. The probability of having a homozygous recessive (ww) offspring is 0.0.
