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Sagot :
Certainly, let's break down and solve each part of the question step by step.
### Part (a)
Question: Mrs Maluleka has two daughters, one in grade 8 and one in grade 10. She pays her school fees on the 21st of January. Calculate how much she paid for school fees on this day.
Solution:
- The school fees per child is R 18,500.
- A 10% discount is applied for early payment before January 25th.
- The discount amount per child = 10% of 18,500 = R 1,850.
- The discounted school fees per child = 18,500 - 1,850 = R 16,650.
- Since she has two daughters and one is also getting a sibling discount:
- The second child gets an additional 10% discount on the original fee of R 18,500 = R 1,850.
- So, the total fee for both daughters = (16,650 + 16,650) - 1,850 = 33,300 - 1,850 = R 31,635.
Therefore, Mrs Maluleka paid R 31,635 for school fees on the 21st of January.
### Part (b)
Question: Calculate the total discount that Mrs Maluleka gets from the school.
Solution:
- Discount for early payment for the first child: R 1,850.
- Discount for early payment for the second child: R 1,850.
- Sibling discount for the second child: R 1,850.
Total discount = 1,850 + 1,850 + 1,850 = R 5,550.
Therefore, the total discount that Mrs Maluleka gets is R 5,550.
### Part (c)
Question: Calculate the total amount that Mrs Maluleka must pay for sundry fees (textbooks, excursions, and uniforms) in 2011.
Solution:
- Textbook fees per child = R 2,000.
- Excursions fee for the daughter in grade 10 = R 1,000.
- Uniforms fee per child = R 1,800.
- She has two daughters, so:
- Total textbook fees = 2 2,000 = R 4,000.
- Total excursions fees = R 1,000.
- Total uniform fees = 2 1,800 = R 3,600.
Total sundry fees = 4,000 + 1,000 + 3,600 = R 8,600.
Therefore, the total amount for sundry fees is R 8,600.
### Part (d)
Question: Mr Tuanyane has a son in grade 11 at Gizembele High School. Calculate the total amount that he must pay for the year.
Solution:
- School fees before discount = R 18,500.
- Early payment discount (since paid by January 21st) = 10% of 18,500 = R 1,850.
- Discounted school fees = 18,500 - 1,850 = R 16,650.
- Textbook fees = R 2,000.
- Excursions fee for grade 11 = R 1,000.
- Uniform fees = R 1,800.
Total amount = 16,650 + 2,000 + 1,000 + 1,800 = R 21,450.
Therefore, the total amount Mr. Tuanyane must pay for the year is R 21,450.
### Part (e)
Question: Mr Tuanyane decides that he wants to pay off his school fees and sundry amounts over a 10 month period (Jan - Oct), calculate how much he must pay per month.
Solution:
- Total amount to be paid = R 21,450 (from part (d)).
- Monthly payment over 10 months = 21,450 / 10 = R 2,145.
Therefore, Mr. Tuanyane must pay R 2,145 per month.
### Part (f)
Question: Gizembele High School's fees for 2012 will be increased by 8.5% and the sundry fees will increase by 6%. Calculate how much Mr Tuanyane will pay in 2012.
Solution:
- School fees for 2011 = R 18,500.
- Increase in school fees = 8.5% of 18,500 = 18,500 1.085 = R 20,072.5.
- Textbook fees for 2011 = R 2,000. Increase in textbook fees = 6% of 2,000 = 2,000 1.06 = R 2,120.
- Excursions fee for 2011 = R 1,000. Increase in excursions fee = 6% of 1,000 = 1,000 1.06 = R 1,060.
- Uniform fees for 2011 = R 1,800. Increase in uniform fees = 6% of 1,800 = 1,800 1.06 = R 1,908.
Total fees for 2012 = 20,072.5 + 2,120 + 1,060 + 1,908 = R 25,160.5.
Therefore, Mr. Tuanyane will pay R 25,160.5 in 2012.
### Part (a)
Question: Mrs Maluleka has two daughters, one in grade 8 and one in grade 10. She pays her school fees on the 21st of January. Calculate how much she paid for school fees on this day.
Solution:
- The school fees per child is R 18,500.
- A 10% discount is applied for early payment before January 25th.
- The discount amount per child = 10% of 18,500 = R 1,850.
- The discounted school fees per child = 18,500 - 1,850 = R 16,650.
- Since she has two daughters and one is also getting a sibling discount:
- The second child gets an additional 10% discount on the original fee of R 18,500 = R 1,850.
- So, the total fee for both daughters = (16,650 + 16,650) - 1,850 = 33,300 - 1,850 = R 31,635.
Therefore, Mrs Maluleka paid R 31,635 for school fees on the 21st of January.
### Part (b)
Question: Calculate the total discount that Mrs Maluleka gets from the school.
Solution:
- Discount for early payment for the first child: R 1,850.
- Discount for early payment for the second child: R 1,850.
- Sibling discount for the second child: R 1,850.
Total discount = 1,850 + 1,850 + 1,850 = R 5,550.
Therefore, the total discount that Mrs Maluleka gets is R 5,550.
### Part (c)
Question: Calculate the total amount that Mrs Maluleka must pay for sundry fees (textbooks, excursions, and uniforms) in 2011.
Solution:
- Textbook fees per child = R 2,000.
- Excursions fee for the daughter in grade 10 = R 1,000.
- Uniforms fee per child = R 1,800.
- She has two daughters, so:
- Total textbook fees = 2 2,000 = R 4,000.
- Total excursions fees = R 1,000.
- Total uniform fees = 2 1,800 = R 3,600.
Total sundry fees = 4,000 + 1,000 + 3,600 = R 8,600.
Therefore, the total amount for sundry fees is R 8,600.
### Part (d)
Question: Mr Tuanyane has a son in grade 11 at Gizembele High School. Calculate the total amount that he must pay for the year.
Solution:
- School fees before discount = R 18,500.
- Early payment discount (since paid by January 21st) = 10% of 18,500 = R 1,850.
- Discounted school fees = 18,500 - 1,850 = R 16,650.
- Textbook fees = R 2,000.
- Excursions fee for grade 11 = R 1,000.
- Uniform fees = R 1,800.
Total amount = 16,650 + 2,000 + 1,000 + 1,800 = R 21,450.
Therefore, the total amount Mr. Tuanyane must pay for the year is R 21,450.
### Part (e)
Question: Mr Tuanyane decides that he wants to pay off his school fees and sundry amounts over a 10 month period (Jan - Oct), calculate how much he must pay per month.
Solution:
- Total amount to be paid = R 21,450 (from part (d)).
- Monthly payment over 10 months = 21,450 / 10 = R 2,145.
Therefore, Mr. Tuanyane must pay R 2,145 per month.
### Part (f)
Question: Gizembele High School's fees for 2012 will be increased by 8.5% and the sundry fees will increase by 6%. Calculate how much Mr Tuanyane will pay in 2012.
Solution:
- School fees for 2011 = R 18,500.
- Increase in school fees = 8.5% of 18,500 = 18,500 1.085 = R 20,072.5.
- Textbook fees for 2011 = R 2,000. Increase in textbook fees = 6% of 2,000 = 2,000 1.06 = R 2,120.
- Excursions fee for 2011 = R 1,000. Increase in excursions fee = 6% of 1,000 = 1,000 1.06 = R 1,060.
- Uniform fees for 2011 = R 1,800. Increase in uniform fees = 6% of 1,800 = 1,800 1.06 = R 1,908.
Total fees for 2012 = 20,072.5 + 2,120 + 1,060 + 1,908 = R 25,160.5.
Therefore, Mr. Tuanyane will pay R 25,160.5 in 2012.
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