To determine the number of oxygen atoms present in one mole of potassium carbonate (K[tex]\(_2\)[/tex]CO[tex]\(_3\)[/tex]), we can follow these steps:
1. Identify the number of oxygen atoms in one molecule of K[tex]\(_2\)[/tex]CO[tex]\(_3\)[/tex]
The chemical formula for potassium carbonate is K[tex]\(_2\)[/tex]CO[tex]\(_3\)[/tex]. This indicates that each molecule of K[tex]\(_2\)[/tex]CO[tex]\(_3\)[/tex] contains:
- 2 potassium (K) atoms
- 1 carbon (C) atom
- 3 oxygen (O) atoms
Therefore, one molecule of potassium carbonate has 3 oxygen atoms.
2. Use Avogadro's number
Avogadro's number is [tex]\(6.022 \times 10^{23}\)[/tex], which represents the number of molecules (or atoms) in one mole of any substance.
3. Calculate the number of oxygen atoms in one mole of K[tex]\(_2\)[/tex]CO[tex]\(_3\)[/tex]
Since one molecule of K[tex]\(_2\)[/tex]CO[tex]\(_3\)[/tex] has 3 oxygen atoms, the number of oxygen atoms in one mole of K[tex]\(_2\)[/tex]CO[tex]\(_3\)[/tex] can be calculated by multiplying the number of oxygen atoms per molecule by Avogadro's number.
[tex]\[
\text{Number of oxygen atoms in one mole of K}_2\text{CO}_3 = 3 \times 6.022 \times 10^{23}
\][/tex]
4. Perform the multiplication
[tex]\[
3 \times 6.022 \times 10^{23} = 1.8066 \times 10^{24}
\][/tex]
So, the number of oxygen atoms in one mole of potassium carbonate (K[tex]\(_2\)[/tex]CO[tex]\(_3\)[/tex]) is [tex]\(1.8066 \times 10^{24}\)[/tex].
Given the options:
A. [tex]\(1.20 \times 10^{24}\)[/tex] atoms
B. [tex]\(1.8 \times 10^{24}\)[/tex] atoms
C. [tex]\(1.8 \times 10^{23}\)[/tex] atoms
D. [tex]\(6.02 \times 10^{23}\)[/tex] atoms
The correct answer is:
B. [tex]\(1.8 \times 10^{24}\)[/tex] atoms
