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How many moles of lithium nitrate (LiNO[tex]\(_3\)[/tex]) are in 256 mL of a 0.855 M solution?

Sagot :

To determine how many moles of lithium nitrate (LiNO₃) are in 256 mL of a 0.855 M solution, we need to perform the following steps:

1. Convert the volume from milliliters to liters:
- Since there are 1000 milliliters (mL) in a liter (L), we convert 256 mL to liters by dividing by 1000.
[tex]\[ \text{Volume in liters} = \frac{256\text{ mL}}{1000} = 0.256\text{ L} \][/tex]

2. Calculate the number of moles using the molarity formula:
- The molarity (M) of a solution is defined as the number of moles of solute per liter of solution. The formula to find the number of moles (n) is:
[tex]\[ \text{Moles} = \text{Molarity} \times \text{Volume in liters} \][/tex]
- Plugging in the given molarity (0.855 M) and the converted volume (0.256 L):
[tex]\[ \text{Moles} = 0.855 \, \text{M} \times 0.256 \, \text{L} = 0.21888 \, \text{moles} \][/tex]

So, there are 0.21888 moles of lithium nitrate (LiNO₃) in 256 mL of a 0.855 M solution.