Find solutions to your problems with the help of IDNLearn.com's knowledgeable users. Our community provides accurate and timely answers to help you understand and solve any issue.
Sagot :
To find the approximate solution to the equation [tex]\(3^{(-x)} - 3 = 4^x - 1\)[/tex] using the given table, let's examine each value of [tex]\(x\)[/tex] step-by-step:
We are tasked with finding the value of [tex]\(x\)[/tex] that makes the left-hand side ([tex]\(3^{(-x)} - 3\)[/tex]) and the right-hand side ([tex]\(4^x - 1\)[/tex]) as close to each other as possible.
Given the table:
[tex]\[ \begin{tabular}{|c|c|c|} \hline $x$ & $3^{(-x)} - 3$ & $4^x - 1$ \\ \hline -1.75 & 3.83 & -0.91 \\ \hline -1.5 & 2.19 & -0.88 \\ \hline -1.25 & 0.95 & -0.82 \\ \hline -1 & 0 & -0.75 \\ \hline -0.75 & -0.72 & -0.65 \\ \hline -0.5 & -1.27 & -0.50 \\ \hline -0.25 & -1.68 & -0.29 \\ \hline \end{tabular} \][/tex]
Let’s compute the absolute differences between [tex]\(3^{(-x)} - 3\)[/tex] and [tex]\(4^x - 1\)[/tex] for each provided [tex]\(x\)[/tex]:
1. For [tex]\(x = -1.75\)[/tex]:
[tex]\[ \left|3.83 - (-0.91)\right| = 3.83 + 0.91 = 4.74 \][/tex]
2. For [tex]\(x = -1.5\)[/tex]:
[tex]\[ \left|2.19 - (-0.88)\right| = 2.19 + 0.88 = 3.07 \][/tex]
3. For [tex]\(x = -1.25\)[/tex]:
[tex]\[ \left|0.95 - (-0.82)\right| = 0.95 + 0.82 = 1.77 \][/tex]
4. For [tex]\(x = -1\)[/tex]:
[tex]\[ \left|0 - (-0.75)\right| = 0 + 0.75 = 0.75 \][/tex]
5. For [tex]\(x = -0.75\)[/tex]:
[tex]\[ \left|-0.72 - (-0.65)\right| = \left|-0.72 + 0.65\right| = \left|-0.07\right| = 0.07 \][/tex]
6. For [tex]\(x = -0.5\)[/tex]:
[tex]\[ \left|-1.27 - (-0.50)\right| = \left|-1.27 + 0.50\right| = \left|-0.77\right| = 0.77 \][/tex]
7. For [tex]\(x = -0.25\)[/tex]:
[tex]\[ \left|-1.68 - (-0.29)\right| = \left|-1.68 + 0.29\right| = \left|-1.39\right| = 1.39 \][/tex]
By comparing the absolute differences, we find that the smallest difference is [tex]\(0.07\)[/tex] when [tex]\(x = -0.75\)[/tex]. Therefore, the approximate solution to the equation [tex]\(3^{(-x)} - 3 = 4^x - 1\)[/tex] is:
[tex]\[ x = -0.75 \][/tex]
Thus, the correct solution in the table is:
[tex]\[ -0.75 \][/tex]
We are tasked with finding the value of [tex]\(x\)[/tex] that makes the left-hand side ([tex]\(3^{(-x)} - 3\)[/tex]) and the right-hand side ([tex]\(4^x - 1\)[/tex]) as close to each other as possible.
Given the table:
[tex]\[ \begin{tabular}{|c|c|c|} \hline $x$ & $3^{(-x)} - 3$ & $4^x - 1$ \\ \hline -1.75 & 3.83 & -0.91 \\ \hline -1.5 & 2.19 & -0.88 \\ \hline -1.25 & 0.95 & -0.82 \\ \hline -1 & 0 & -0.75 \\ \hline -0.75 & -0.72 & -0.65 \\ \hline -0.5 & -1.27 & -0.50 \\ \hline -0.25 & -1.68 & -0.29 \\ \hline \end{tabular} \][/tex]
Let’s compute the absolute differences between [tex]\(3^{(-x)} - 3\)[/tex] and [tex]\(4^x - 1\)[/tex] for each provided [tex]\(x\)[/tex]:
1. For [tex]\(x = -1.75\)[/tex]:
[tex]\[ \left|3.83 - (-0.91)\right| = 3.83 + 0.91 = 4.74 \][/tex]
2. For [tex]\(x = -1.5\)[/tex]:
[tex]\[ \left|2.19 - (-0.88)\right| = 2.19 + 0.88 = 3.07 \][/tex]
3. For [tex]\(x = -1.25\)[/tex]:
[tex]\[ \left|0.95 - (-0.82)\right| = 0.95 + 0.82 = 1.77 \][/tex]
4. For [tex]\(x = -1\)[/tex]:
[tex]\[ \left|0 - (-0.75)\right| = 0 + 0.75 = 0.75 \][/tex]
5. For [tex]\(x = -0.75\)[/tex]:
[tex]\[ \left|-0.72 - (-0.65)\right| = \left|-0.72 + 0.65\right| = \left|-0.07\right| = 0.07 \][/tex]
6. For [tex]\(x = -0.5\)[/tex]:
[tex]\[ \left|-1.27 - (-0.50)\right| = \left|-1.27 + 0.50\right| = \left|-0.77\right| = 0.77 \][/tex]
7. For [tex]\(x = -0.25\)[/tex]:
[tex]\[ \left|-1.68 - (-0.29)\right| = \left|-1.68 + 0.29\right| = \left|-1.39\right| = 1.39 \][/tex]
By comparing the absolute differences, we find that the smallest difference is [tex]\(0.07\)[/tex] when [tex]\(x = -0.75\)[/tex]. Therefore, the approximate solution to the equation [tex]\(3^{(-x)} - 3 = 4^x - 1\)[/tex] is:
[tex]\[ x = -0.75 \][/tex]
Thus, the correct solution in the table is:
[tex]\[ -0.75 \][/tex]
We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. For dependable answers, trust IDNLearn.com. Thank you for visiting, and we look forward to helping you again soon.