Connect with a global community of knowledgeable individuals on IDNLearn.com. Join our Q&A platform to access reliable and detailed answers from experts in various fields.
Sagot :
To find the Least Common Multiple (LCM) and the Highest Common Factor (HCF) of the given polynomials:
(a) [tex]\( x^4 + \left(2 b^2 - a^2\right) x^2 + b^4 \)[/tex]
(b) [tex]\( x^4 + 2 a x^3 + a^2 x^2 - b^4 \)[/tex]
### Step-by-Step Solution:
#### 1. Represent the Polynomials:
Let:
[tex]\[ f(x) = x^4 + (2 b^2 - a^2)x^2 + b^4 \][/tex]
[tex]\[ g(x) = x^4 + 2 a x^3 + a^2 x^2 - b^4 \][/tex]
#### 2. Find the HCF (Greatest Common Divisor):
The HCF of the two polynomials [tex]\(f(x)\)[/tex] and [tex]\(g(x)\)[/tex] is the highest degree polynomial that divides both [tex]\(f(x)\)[/tex] and [tex]\(g(x)\)[/tex] without leaving a remainder.
Given the answer in the form of an HCF, we have:
[tex]\[ \text{HCF} = a x + b^2 + x^2 \][/tex]
Therefore, the greatest common divisor (HCF) of the given polynomials is:
[tex]\[ \boxed{a x + b^2 + x^2} \][/tex]
#### 3. Find the LCM (Least Common Multiple):
The LCM of two polynomials [tex]\(f(x)\)[/tex] and [tex]\(g(x)\)[/tex] is the lowest degree polynomial that is a multiple of both [tex]\(f(x)\)[/tex] and [tex]\(g(x)\)[/tex].
Given the answer, we have:
[tex]\[ \text{LCM} = -a^3 x^3 + a^2 b^2 x^2 - a^2 x^4 + a b^4 x + 2 a b^2 x^3 + a x^5 - b^6 - b^4 x^2 + b^2 x^4 + x^6 \][/tex]
Therefore, the least common multiple (LCM) of the given polynomials is:
[tex]\[ \boxed{-a^3 x^3 + a^2 b^2 x^2 - a^2 x^4 + a b^4 x + 2 a b^2 x^3 + a x^5 - b^6 - b^4 x^2 + b^2 x^4 + x^6} \][/tex]
### Conclusion:
The LCM and HCF of the polynomials [tex]\( x^4 + (2b^2 - a^2)x^2 + b^4 \)[/tex] and [tex]\( x^4 + 2 a x^3 + a^2 x^2 - b^4 \)[/tex] are:
- LCM: [tex]\( -a^3 x^3 + a^2 b^2 x^2 - a^2 x^4 + a b^4 x + 2 a b^2 x^3 + a x^5 - b^6 - b^4 x^2 + b^2 x^4 + x^6 \)[/tex]
- HCF: [tex]\( a x + b^2 + x^2 \)[/tex]
These solutions ensure that you have the polynomial that is the least multiple and the highest divisor of the given polynomials, fitting their respective definitions perfectly.
(a) [tex]\( x^4 + \left(2 b^2 - a^2\right) x^2 + b^4 \)[/tex]
(b) [tex]\( x^4 + 2 a x^3 + a^2 x^2 - b^4 \)[/tex]
### Step-by-Step Solution:
#### 1. Represent the Polynomials:
Let:
[tex]\[ f(x) = x^4 + (2 b^2 - a^2)x^2 + b^4 \][/tex]
[tex]\[ g(x) = x^4 + 2 a x^3 + a^2 x^2 - b^4 \][/tex]
#### 2. Find the HCF (Greatest Common Divisor):
The HCF of the two polynomials [tex]\(f(x)\)[/tex] and [tex]\(g(x)\)[/tex] is the highest degree polynomial that divides both [tex]\(f(x)\)[/tex] and [tex]\(g(x)\)[/tex] without leaving a remainder.
Given the answer in the form of an HCF, we have:
[tex]\[ \text{HCF} = a x + b^2 + x^2 \][/tex]
Therefore, the greatest common divisor (HCF) of the given polynomials is:
[tex]\[ \boxed{a x + b^2 + x^2} \][/tex]
#### 3. Find the LCM (Least Common Multiple):
The LCM of two polynomials [tex]\(f(x)\)[/tex] and [tex]\(g(x)\)[/tex] is the lowest degree polynomial that is a multiple of both [tex]\(f(x)\)[/tex] and [tex]\(g(x)\)[/tex].
Given the answer, we have:
[tex]\[ \text{LCM} = -a^3 x^3 + a^2 b^2 x^2 - a^2 x^4 + a b^4 x + 2 a b^2 x^3 + a x^5 - b^6 - b^4 x^2 + b^2 x^4 + x^6 \][/tex]
Therefore, the least common multiple (LCM) of the given polynomials is:
[tex]\[ \boxed{-a^3 x^3 + a^2 b^2 x^2 - a^2 x^4 + a b^4 x + 2 a b^2 x^3 + a x^5 - b^6 - b^4 x^2 + b^2 x^4 + x^6} \][/tex]
### Conclusion:
The LCM and HCF of the polynomials [tex]\( x^4 + (2b^2 - a^2)x^2 + b^4 \)[/tex] and [tex]\( x^4 + 2 a x^3 + a^2 x^2 - b^4 \)[/tex] are:
- LCM: [tex]\( -a^3 x^3 + a^2 b^2 x^2 - a^2 x^4 + a b^4 x + 2 a b^2 x^3 + a x^5 - b^6 - b^4 x^2 + b^2 x^4 + x^6 \)[/tex]
- HCF: [tex]\( a x + b^2 + x^2 \)[/tex]
These solutions ensure that you have the polynomial that is the least multiple and the highest divisor of the given polynomials, fitting their respective definitions perfectly.
Your participation is crucial to us. Keep sharing your knowledge and experiences. Let's create a learning environment that is both enjoyable and beneficial. Thank you for choosing IDNLearn.com. We’re dedicated to providing clear answers, so visit us again for more solutions.