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Sagot :
To find the slope of the line given by the equation [tex]\( y = -4x + 15 \)[/tex], we need to recall the slope-intercept form of a linear equation, which is [tex]\( y = mx + b \)[/tex].
In this general form:
- [tex]\( m \)[/tex] represents the slope of the line.
- [tex]\( b \)[/tex] represents the y-intercept, which is the point where the line crosses the y-axis.
Let's compare the given equation [tex]\( y = -4x + 15 \)[/tex] with the slope-intercept form [tex]\( y = mx + b \)[/tex].
Here, [tex]\( m \)[/tex] is the coefficient of [tex]\( x \)[/tex]. In this equation, the coefficient of [tex]\( x \)[/tex] is [tex]\(-4\)[/tex].
Thus, the slope [tex]\( m \)[/tex] of the line [tex]\( y = -4x + 15 \)[/tex] is [tex]\(-4\)[/tex].
In this general form:
- [tex]\( m \)[/tex] represents the slope of the line.
- [tex]\( b \)[/tex] represents the y-intercept, which is the point where the line crosses the y-axis.
Let's compare the given equation [tex]\( y = -4x + 15 \)[/tex] with the slope-intercept form [tex]\( y = mx + b \)[/tex].
Here, [tex]\( m \)[/tex] is the coefficient of [tex]\( x \)[/tex]. In this equation, the coefficient of [tex]\( x \)[/tex] is [tex]\(-4\)[/tex].
Thus, the slope [tex]\( m \)[/tex] of the line [tex]\( y = -4x + 15 \)[/tex] is [tex]\(-4\)[/tex].
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