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Sagot :
Para determinar qué afirmación es verdadera, analicemos cada uno de los enunciados uno por uno:
a) [tex]\(-\frac{4}{9}\)[/tex] [tex]\(\square\)[/tex] [tex]\(-\frac{3}{8}\)[/tex]
- Primero, compararemos los valores de [tex]\(-\frac{4}{9}\)[/tex] y [tex]\(-\frac{3}{8}\)[/tex].
- [tex]\(-\frac{4}{9}\)[/tex] es aproximadamente [tex]\(-0.444...\)[/tex]
- [tex]\(-\frac{3}{8}\)[/tex] es aproximadamente [tex]\(-0.375\)[/tex]
- Claramente, [tex]\(-0.444...\)[/tex] no es igual a [tex]\(-0.375\)[/tex].
b) [tex]\(\frac{-6}{5}\)[/tex] [tex]\(\square\)[/tex] 5
- [tex]\(\frac{-6}{5}\)[/tex] es [tex]\(-1.2\)[/tex].
- Comparando [tex]\(-1.2\)[/tex] y 5, claramente [tex]\(-1.2\)[/tex] no es mayor que 5.
c) [tex]\(-\frac{1}{5}\)[/tex] [tex]\(\square\)[/tex] [tex]\(-20\)[/tex]
- [tex]\(-\frac{1}{5}\)[/tex] es [tex]\(-0.2\)[/tex].
- Comparando [tex]\(-0.2\)[/tex] y [tex]\(-20\)[/tex], claramente [tex]\(-0.2\)[/tex] no es menor que [tex]\(-20\)[/tex].
d) [tex]\(-\frac{1}{5}\)[/tex] [tex]\(\square\)[/tex] [tex]\(-20\)[/tex]
- [tex]\(-\frac{1}{5}\)[/tex] es [tex]\(-0.2\)[/tex].
- Comparando [tex]\(-0.2\)[/tex] y [tex]\(-20\)[/tex], claramente [tex]\(-0.2\)[/tex] es mayor que [tex]\(-20\)[/tex].
e) [tex]\(\frac{9}{9}\)[/tex] [tex]\(\square\)[/tex] 1
- [tex]\(\frac{9}{9}\)[/tex] es [tex]\(1\)[/tex].
- Comparando [tex]\(1\)[/tex] y [tex]\(1\)[/tex], ambos son iguales.
Examinando estas comparaciones, observamos que la afirmación que resulta verdadera es:
d) [tex]\(-\frac{1}{5}\)[/tex] es mayor que [tex]\(-20\)[/tex].
Por lo tanto, la respuesta correcta a la pregunta es:
4 (d)
a) [tex]\(-\frac{4}{9}\)[/tex] [tex]\(\square\)[/tex] [tex]\(-\frac{3}{8}\)[/tex]
- Primero, compararemos los valores de [tex]\(-\frac{4}{9}\)[/tex] y [tex]\(-\frac{3}{8}\)[/tex].
- [tex]\(-\frac{4}{9}\)[/tex] es aproximadamente [tex]\(-0.444...\)[/tex]
- [tex]\(-\frac{3}{8}\)[/tex] es aproximadamente [tex]\(-0.375\)[/tex]
- Claramente, [tex]\(-0.444...\)[/tex] no es igual a [tex]\(-0.375\)[/tex].
b) [tex]\(\frac{-6}{5}\)[/tex] [tex]\(\square\)[/tex] 5
- [tex]\(\frac{-6}{5}\)[/tex] es [tex]\(-1.2\)[/tex].
- Comparando [tex]\(-1.2\)[/tex] y 5, claramente [tex]\(-1.2\)[/tex] no es mayor que 5.
c) [tex]\(-\frac{1}{5}\)[/tex] [tex]\(\square\)[/tex] [tex]\(-20\)[/tex]
- [tex]\(-\frac{1}{5}\)[/tex] es [tex]\(-0.2\)[/tex].
- Comparando [tex]\(-0.2\)[/tex] y [tex]\(-20\)[/tex], claramente [tex]\(-0.2\)[/tex] no es menor que [tex]\(-20\)[/tex].
d) [tex]\(-\frac{1}{5}\)[/tex] [tex]\(\square\)[/tex] [tex]\(-20\)[/tex]
- [tex]\(-\frac{1}{5}\)[/tex] es [tex]\(-0.2\)[/tex].
- Comparando [tex]\(-0.2\)[/tex] y [tex]\(-20\)[/tex], claramente [tex]\(-0.2\)[/tex] es mayor que [tex]\(-20\)[/tex].
e) [tex]\(\frac{9}{9}\)[/tex] [tex]\(\square\)[/tex] 1
- [tex]\(\frac{9}{9}\)[/tex] es [tex]\(1\)[/tex].
- Comparando [tex]\(1\)[/tex] y [tex]\(1\)[/tex], ambos son iguales.
Examinando estas comparaciones, observamos que la afirmación que resulta verdadera es:
d) [tex]\(-\frac{1}{5}\)[/tex] es mayor que [tex]\(-20\)[/tex].
Por lo tanto, la respuesta correcta a la pregunta es:
4 (d)
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