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Sagot :
To calculate the energy of a photon, we use the formula derived from Planck's relation, which states:
[tex]\[ E = h \cdot f \][/tex]
where:
- [tex]\( E \)[/tex] is the energy of the photon,
- [tex]\( h \)[/tex] is Planck's constant,
- [tex]\( f \)[/tex] is the frequency of the photon.
Given the values:
- Frequency [tex]\( f = 6.95 \times 10^{14} \text{ Hz} \)[/tex]
- Planck's constant [tex]\( h = 6.63 \times 10^{-34} \text{ J} \cdot \text{s} \)[/tex]
We substitute these values into the formula:
[tex]\[ E = (6.63 \times 10^{-34} \text{ J} \cdot \text{s}) \times (6.95 \times 10^{14} \text{ Hz}) \][/tex]
After performing the multiplication, we obtain:
[tex]\[ E = 4.61 \times 10^{-19} \text{ J} \][/tex]
Thus, the energy of a photon of light with a frequency of [tex]\( 6.95 \times 10^{14} \text{ Hz} \)[/tex] is:
[tex]\[ \boxed{4.61 \times 10^{-19} \text{ J}} \][/tex]
[tex]\[ E = h \cdot f \][/tex]
where:
- [tex]\( E \)[/tex] is the energy of the photon,
- [tex]\( h \)[/tex] is Planck's constant,
- [tex]\( f \)[/tex] is the frequency of the photon.
Given the values:
- Frequency [tex]\( f = 6.95 \times 10^{14} \text{ Hz} \)[/tex]
- Planck's constant [tex]\( h = 6.63 \times 10^{-34} \text{ J} \cdot \text{s} \)[/tex]
We substitute these values into the formula:
[tex]\[ E = (6.63 \times 10^{-34} \text{ J} \cdot \text{s}) \times (6.95 \times 10^{14} \text{ Hz}) \][/tex]
After performing the multiplication, we obtain:
[tex]\[ E = 4.61 \times 10^{-19} \text{ J} \][/tex]
Thus, the energy of a photon of light with a frequency of [tex]\( 6.95 \times 10^{14} \text{ Hz} \)[/tex] is:
[tex]\[ \boxed{4.61 \times 10^{-19} \text{ J}} \][/tex]
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