Get the answers you've been looking for with the help of IDNLearn.com's expert community. Our Q&A platform offers reliable and thorough answers to help you make informed decisions quickly and easily.
Sagot :
To calculate the energy of a photon, we use the formula derived from Planck's relation, which states:
[tex]\[ E = h \cdot f \][/tex]
where:
- [tex]\( E \)[/tex] is the energy of the photon,
- [tex]\( h \)[/tex] is Planck's constant,
- [tex]\( f \)[/tex] is the frequency of the photon.
Given the values:
- Frequency [tex]\( f = 6.95 \times 10^{14} \text{ Hz} \)[/tex]
- Planck's constant [tex]\( h = 6.63 \times 10^{-34} \text{ J} \cdot \text{s} \)[/tex]
We substitute these values into the formula:
[tex]\[ E = (6.63 \times 10^{-34} \text{ J} \cdot \text{s}) \times (6.95 \times 10^{14} \text{ Hz}) \][/tex]
After performing the multiplication, we obtain:
[tex]\[ E = 4.61 \times 10^{-19} \text{ J} \][/tex]
Thus, the energy of a photon of light with a frequency of [tex]\( 6.95 \times 10^{14} \text{ Hz} \)[/tex] is:
[tex]\[ \boxed{4.61 \times 10^{-19} \text{ J}} \][/tex]
[tex]\[ E = h \cdot f \][/tex]
where:
- [tex]\( E \)[/tex] is the energy of the photon,
- [tex]\( h \)[/tex] is Planck's constant,
- [tex]\( f \)[/tex] is the frequency of the photon.
Given the values:
- Frequency [tex]\( f = 6.95 \times 10^{14} \text{ Hz} \)[/tex]
- Planck's constant [tex]\( h = 6.63 \times 10^{-34} \text{ J} \cdot \text{s} \)[/tex]
We substitute these values into the formula:
[tex]\[ E = (6.63 \times 10^{-34} \text{ J} \cdot \text{s}) \times (6.95 \times 10^{14} \text{ Hz}) \][/tex]
After performing the multiplication, we obtain:
[tex]\[ E = 4.61 \times 10^{-19} \text{ J} \][/tex]
Thus, the energy of a photon of light with a frequency of [tex]\( 6.95 \times 10^{14} \text{ Hz} \)[/tex] is:
[tex]\[ \boxed{4.61 \times 10^{-19} \text{ J}} \][/tex]
We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Thank you for visiting IDNLearn.com. For reliable answers to all your questions, please visit us again soon.