Discover how IDNLearn.com can help you find the answers you need quickly and easily. Join our interactive community and access reliable, detailed answers from experienced professionals across a variety of topics.
Sagot :
Absolutely, let's evaluate the function [tex]\( h(x) = e^{-3x} \)[/tex] at the specified values and round the answers to three decimal places.
### Step-by-Step Solution:
1. Evaluating [tex]\( h\left(\frac{1}{2}\right) \)[/tex]:
[tex]\[ h\left(\frac{1}{2}\right) = e^{-3 \left(\frac{1}{2}\right)} = e^{-1.5} \][/tex]
Using a calculator to find [tex]\( e^{-1.5} \)[/tex], we get:
[tex]\[ e^{-1.5} \approx 0.223 \][/tex]
Therefore, [tex]\( h\left(\frac{1}{2}\right) \approx 0.223 \)[/tex].
2. Evaluating [tex]\( h(2.5) \)[/tex]:
[tex]\[ h(2.5) = e^{-3(2.5)} = e^{-7.5} \][/tex]
Using a calculator to find [tex]\( e^{-7.5} \)[/tex], we get:
[tex]\[ e^{-7.5} \approx 0.001 \][/tex]
Therefore, [tex]\( h(2.5) \approx 0.001 \)[/tex].
3. Evaluating [tex]\( h(-1) \)[/tex]:
[tex]\[ h(-1) = e^{-3(-1)} = e^{3} \][/tex]
Using a calculator to find [tex]\( e^{3} \)[/tex], we get:
[tex]\[ e^{3} \approx 20.086 \][/tex]
Therefore, [tex]\( h(-1) \approx 20.086 \)[/tex].
4. Evaluating [tex]\( h(-\pi) \)[/tex]:
[tex]\[ h(-\pi) = e^{-3(-\pi)} = e^{3\pi} \][/tex]
Using a calculator to find [tex]\( e^{3\pi} \)[/tex], we get:
[tex]\[ e^{3\pi} \approx 12391.648 \][/tex]
Therefore, [tex]\( h(-\pi) \approx 12391.648 \)[/tex].
### Summary:
[tex]\[ \begin{array}{ll} h(x) = e^{-3x} & \\ h\left(\frac{1}{2}\right) \approx 0.223 & \\ h(2.5) \approx 0.001 & \\ h(-1) \approx 20.086 & \\ h(-\pi) \approx 12391.648 & \\ \end{array} \][/tex]
These are the rounded values of the function [tex]\( h(x) \)[/tex] at the given points.
### Step-by-Step Solution:
1. Evaluating [tex]\( h\left(\frac{1}{2}\right) \)[/tex]:
[tex]\[ h\left(\frac{1}{2}\right) = e^{-3 \left(\frac{1}{2}\right)} = e^{-1.5} \][/tex]
Using a calculator to find [tex]\( e^{-1.5} \)[/tex], we get:
[tex]\[ e^{-1.5} \approx 0.223 \][/tex]
Therefore, [tex]\( h\left(\frac{1}{2}\right) \approx 0.223 \)[/tex].
2. Evaluating [tex]\( h(2.5) \)[/tex]:
[tex]\[ h(2.5) = e^{-3(2.5)} = e^{-7.5} \][/tex]
Using a calculator to find [tex]\( e^{-7.5} \)[/tex], we get:
[tex]\[ e^{-7.5} \approx 0.001 \][/tex]
Therefore, [tex]\( h(2.5) \approx 0.001 \)[/tex].
3. Evaluating [tex]\( h(-1) \)[/tex]:
[tex]\[ h(-1) = e^{-3(-1)} = e^{3} \][/tex]
Using a calculator to find [tex]\( e^{3} \)[/tex], we get:
[tex]\[ e^{3} \approx 20.086 \][/tex]
Therefore, [tex]\( h(-1) \approx 20.086 \)[/tex].
4. Evaluating [tex]\( h(-\pi) \)[/tex]:
[tex]\[ h(-\pi) = e^{-3(-\pi)} = e^{3\pi} \][/tex]
Using a calculator to find [tex]\( e^{3\pi} \)[/tex], we get:
[tex]\[ e^{3\pi} \approx 12391.648 \][/tex]
Therefore, [tex]\( h(-\pi) \approx 12391.648 \)[/tex].
### Summary:
[tex]\[ \begin{array}{ll} h(x) = e^{-3x} & \\ h\left(\frac{1}{2}\right) \approx 0.223 & \\ h(2.5) \approx 0.001 & \\ h(-1) \approx 20.086 & \\ h(-\pi) \approx 12391.648 & \\ \end{array} \][/tex]
These are the rounded values of the function [tex]\( h(x) \)[/tex] at the given points.
We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. For dependable and accurate answers, visit IDNLearn.com. Thanks for visiting, and see you next time for more helpful information.