Get detailed and accurate responses to your questions on IDNLearn.com. Ask your questions and receive prompt, detailed answers from our experienced and knowledgeable community members.
Sagot :
To find the equation of a circle given the center and the endpoints of a diameter, follow these steps:
1. Identify the center of the circle:
The center of the circle is [tex]\((-3, -4)\)[/tex].
2. Calculate the radius of the circle:
Use the distance formula to find the length of the diameter first. The formula for the distance between two points [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex] is:
[tex]\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \][/tex]
The given endpoints of the diameter are [tex]\((0, 2)\)[/tex] and [tex]\((-6, -10)\)[/tex]. Plugging in these values:
[tex]\[ d = \sqrt{(0 - (-6))^2 + (2 - (-10))^2} = \sqrt{6^2 + 12^2} = \sqrt{36 + 144} = \sqrt{180} \][/tex]
The diameter is [tex]\(\sqrt{180}\)[/tex], and the radius [tex]\(r\)[/tex] is half of the diameter:
[tex]\[ r = \frac{\sqrt{180}}{2} = \sqrt{45} \approx 6.708203932499369 \][/tex]
3. Formulate the equation of the circle:
The general form of the equation of a circle is [tex]\((x - h)^2 + (y - k)^2 = r^2\)[/tex], where [tex]\((h, k)\)[/tex] is the center and [tex]\(r\)[/tex] is the radius.
Here, the center [tex]\((h, k) = (-3, -4)\)[/tex], and [tex]\(r^2 = (\sqrt{45})^2 = 45\)[/tex].
Thus, the equation of the circle is:
[tex]\[ (x - (-3))^2 + (y - (-4))^2 = 45 \][/tex]
Simplifying:
[tex]\[ (x + 3)^2 + (y + 4)^2 = 45 \][/tex]
So filling in the provided boxes:
[tex]\[ \boxed{ -3 } \;\;\boxed{ -4 }\;\;\boxed{ 45 } \][/tex]
The final equation is:
[tex]\[ (x + 3)^2 + (y + 4)^2 = 45 \][/tex]
1. Identify the center of the circle:
The center of the circle is [tex]\((-3, -4)\)[/tex].
2. Calculate the radius of the circle:
Use the distance formula to find the length of the diameter first. The formula for the distance between two points [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex] is:
[tex]\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \][/tex]
The given endpoints of the diameter are [tex]\((0, 2)\)[/tex] and [tex]\((-6, -10)\)[/tex]. Plugging in these values:
[tex]\[ d = \sqrt{(0 - (-6))^2 + (2 - (-10))^2} = \sqrt{6^2 + 12^2} = \sqrt{36 + 144} = \sqrt{180} \][/tex]
The diameter is [tex]\(\sqrt{180}\)[/tex], and the radius [tex]\(r\)[/tex] is half of the diameter:
[tex]\[ r = \frac{\sqrt{180}}{2} = \sqrt{45} \approx 6.708203932499369 \][/tex]
3. Formulate the equation of the circle:
The general form of the equation of a circle is [tex]\((x - h)^2 + (y - k)^2 = r^2\)[/tex], where [tex]\((h, k)\)[/tex] is the center and [tex]\(r\)[/tex] is the radius.
Here, the center [tex]\((h, k) = (-3, -4)\)[/tex], and [tex]\(r^2 = (\sqrt{45})^2 = 45\)[/tex].
Thus, the equation of the circle is:
[tex]\[ (x - (-3))^2 + (y - (-4))^2 = 45 \][/tex]
Simplifying:
[tex]\[ (x + 3)^2 + (y + 4)^2 = 45 \][/tex]
So filling in the provided boxes:
[tex]\[ \boxed{ -3 } \;\;\boxed{ -4 }\;\;\boxed{ 45 } \][/tex]
The final equation is:
[tex]\[ (x + 3)^2 + (y + 4)^2 = 45 \][/tex]
We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. IDNLearn.com is committed to providing the best answers. Thank you for visiting, and see you next time for more solutions.