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Find the rational number between [tex]\frac{3}{7}[/tex] and [tex]\frac{6}{10}[/tex].

Sagot :

Sure, let's find a rational number between [tex]\(\frac{3}{7}\)[/tex] and [tex]\(\frac{6}{10}\)[/tex].

### Step-by-Step Solution

Step 1: Convert the fractions to a common denominator.

First, let's convert both fractions, [tex]\(\frac{3}{7}\)[/tex] and [tex]\(\frac{6}{10}\)[/tex], to have a common denominator. To do this, we can find the least common multiple (LCM) of the denominators 7 and 10.

The LCM of 7 and 10 is 70.

Now, let's rewrite the fractions with this common denominator:
- [tex]\(\frac{3}{7}\)[/tex]:
Convert to a denominator of 70:
[tex]\[ \frac{3}{7} = \frac{3 \times 10}{7 \times 10} = \frac{30}{70} \][/tex]

- [tex]\(\frac{6}{10}\)[/tex]:
Convert to a denominator of 70:
[tex]\[ \frac{6}{10} = \frac{6 \times 7}{10 \times 7} = \frac{42}{70} \][/tex]

So, [tex]\(\frac{3}{7} = \frac{30}{70}\)[/tex] and [tex]\(\frac{6}{10} = \frac{42}{70}\)[/tex].

Step 2: Check for Rational Numbers Between the Two Fractions

We need to find a rational number that lies between [tex]\(\frac{30}{70}\)[/tex] and [tex]\(\frac{42}{70}\)[/tex].

Step 3: Calculate the Average as a Middle Fraction

One reliable way to find a rational number between two fractions is to take their average.

Calculate the average of [tex]\(\frac{30}{70}\)[/tex] and [tex]\(\frac{42}{70}\)[/tex]:
[tex]\[ \text{Average} = \frac{\frac{30}{70} + \frac{42}{70}}{2} = \frac{30 + 42}{2 \times 70} = \frac{72}{140} \][/tex]

Step 4: Simplify the Resulting Fraction

Now, simplify [tex]\(\frac{72}{140}\)[/tex]:
- The greatest common divisor (GCD) of 72 and 140 is 2.

Simplify by dividing the numerator and the denominator by their GCD:
[tex]\[ \frac{72 \div 2}{140 \div 2} = \frac{36}{70} = \frac{18}{35} \][/tex]

Final Result:

The fraction [tex]\(\frac{18}{35}\)[/tex] is a rational number between [tex]\(\frac{3}{7}\)[/tex] and [tex]\(\frac{6}{10}\)[/tex].

So, a rational number between [tex]\(\frac{3}{7}\)[/tex] and [tex]\(\frac{6}{10}\)[/tex] is [tex]\(\frac{18}{35}\)[/tex].