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Let [tex]\( A \)[/tex] be the set of integers 1 through 10, and [tex]\( B \)[/tex] the set of multiples of 4 less than 15.

Find [tex]\( A \cap B \)[/tex].

Sagot :

GinnyAnsweridn
Sure, let's solve the problem step-by-step:

1. Define Set A:
Set A consists of integers from 1 through 10. Therefore:
[tex]\[ A = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10\} \][/tex]

2. Define Set B:
Set B consists of multiples of 4 that are less than 15. The multiples of 4 under 15 are:
[tex]\[ 4, 8, 12 \][/tex]
However, 12 is not less than 15, so we remove it. Hence:
[tex]\[ B = \{4, 8\} \][/tex]

3. Find the Intersection of Sets A and B:
The intersection of sets A and B, denoted as [tex]\( A \cap B \)[/tex], consists of elements that are common to both sets. By examining sets A and B:
[tex]\[ A \cap B = \{4, 8\} \][/tex]

Therefore, the intersection of sets A and B is:
[tex]\[ \{4, 8\} \][/tex]
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