Let's solve each question step-by-step:
### Question 15
Mrs. Kramer's class needs at least \[tex]$120 and they have already collected \$[/tex]85. We need to find out how much more money, [tex]\(c\)[/tex], they need to collect.
The amount they still need can be calculated as follows:
[tex]\[ c = 120 - 85 \][/tex]
Hence, [tex]\( c = 35 \)[/tex].
The inequality must express that [tex]\( \$85 + c \)[/tex] is at least [tex]\( \$120 \)[/tex].
[tex]\[ 85 + c \geq 120 \][/tex]
So the correct answer is:
[tex]\[ \boxed{85 + c \geq 120 \text{ (D)}} \][/tex]
### Question 17
Mike is thinking of a number [tex]\( n \)[/tex]. He knows that ten times the number is less than 70. We need to form an inequality that correctly describes this situation.
The statement “ten times the number [tex]\( n \)[/tex] is less than 70” can be written as:
[tex]\[ 10n < 70 \][/tex]
Hence, the correct answer is:
[tex]\[ \boxed{10n < 70 \text{ (A)}} \][/tex]
### Question 19
Tracy has \[tex]$35 to spend on comic books and a movie ticket. Each comic book costs \$[/tex]3, and the movie ticket costs \[tex]$10. We need to determine how many comic books, \( b \), Tracy can buy.
First, subtract the cost of the movie ticket from the total amount Tracy has:
\[ 35 - 10 = 25 \]
The remaining money is \$[/tex]25, which is all Tracy has left to purchase comic books. Since each comic book costs \[tex]$3, we form an inequality for \( b \) as:
\[ 35 - 3b \leq 10 \]
This inequality shows that the money left after spending on the movie ticket and comic books should be less than or equal to \$[/tex]10.
Therefore, the correct answer is:
[tex]\[ \boxed{35 - 3b \leq 10 \text{ (A)}} \][/tex]
Summarizing:
1. [tex]\( \boxed{D. \, 85 + c \geq 120} \)[/tex]
2. [tex]\( \boxed{A. \, 10n < 70} \)[/tex]
3. [tex]\( \boxed{A. \, 35 - 3b \leq 10} \)[/tex]
