IDNLearn.com provides a user-friendly platform for finding and sharing accurate answers. Find in-depth and accurate answers to all your questions from our knowledgeable and dedicated community members.
Sagot :
In this case, you just multiply the expression under the root that gave the greatest integer (as you pull the square root of that number). See how I did: 4 multiplied by 31, which gives 124 then pull out the square root of 4, because 31 can not be, because it is a prime number and root would be an irrational number.
[tex]\sqrt{124}=\sqrt{4*31}=\sqrt{31}*\sqrt{4}=2\sqrt{31}=~11.14[/tex]
[tex]\sqrt{124}=\sqrt{4*31}=\sqrt{31}*\sqrt{4}=2\sqrt{31}=~11.14[/tex]
Hi,
Think about your perfect squares: 1, 4, 9, 16, 25, etc.
Therefore, do any of these perfect squares go into 124? Yes, 124 goes into 4, 31 times and therefore we can say:
[ square root of 4 ] [ square root of 31 ]
Now, the square root of 4 is a perfect square which can be simplified down to:
2 square root of 31 <==== FINAL ANSWER
Think about your perfect squares: 1, 4, 9, 16, 25, etc.
Therefore, do any of these perfect squares go into 124? Yes, 124 goes into 4, 31 times and therefore we can say:
[ square root of 4 ] [ square root of 31 ]
Now, the square root of 4 is a perfect square which can be simplified down to:
2 square root of 31 <==== FINAL ANSWER
We are delighted to have you as part of our community. Keep asking, answering, and sharing your insights. Together, we can create a valuable knowledge resource. IDNLearn.com is your go-to source for accurate answers. Thanks for stopping by, and come back for more helpful information.