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Find the inverse of the given function.

[tex]\[
\begin{array}{l}
h(x) = \frac{2x - 4}{3} \\
h^{-1}(x) = \frac{3}{(2x - 4)} \\
h^{-1}(x) = \frac{3x - 12}{2} \\
h^{-1}(x) = \frac{3x + 4}{2} \\
\end{array}
\][/tex]


Sagot :

To find the inverse of the given function [tex]\(h(x) = \frac{2x - 4}{3}\)[/tex], we need to follow these steps:

1. Express the function in terms of [tex]\(y\)[/tex]:
[tex]\[ y = \frac{2x - 4}{3} \][/tex]

2. Swap [tex]\(x\)[/tex] and [tex]\(y\)[/tex]:
To find the inverse function, we switch the roles of [tex]\(x\)[/tex] and [tex]\(y\)[/tex] in the equation:
[tex]\[ x = \frac{2y - 4}{3} \][/tex]

3. Solve for [tex]\(y\)[/tex]:
We now solve this equation for [tex]\(y\)[/tex]:
[tex]\[ x = \frac{2y - 4}{3} \][/tex]
To isolate [tex]\(y\)[/tex], we first multiply both sides by 3:
[tex]\[ 3x = 2y - 4 \][/tex]

4. Isolate [tex]\(y\)[/tex]:
Add 4 to both sides of the equation:
[tex]\[ 3x + 4 = 2y \][/tex]

5. Divide by 2:
Finally, divide by 2 to isolate [tex]\(y\)[/tex]:
[tex]\[ y = \frac{3x + 4}{2} \][/tex]

Thus, the inverse function [tex]\(h^{-1}(x)\)[/tex] is:
[tex]\[ h^{-1}(x) = \frac{3x + 4}{2} \][/tex]

This is the inverse of the given function [tex]\(h(x) = \frac{2x - 4}{3}\)[/tex].