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Sagot :
Let's evaluate the function [tex]\( g(x) \)[/tex] at the given points step-by-step:
1. Evaluate [tex]\( g(-4) \)[/tex]:
- For [tex]\( x = -4 \)[/tex]:
- Since [tex]\(-5 \leq -4 \leq -1\)[/tex], we use the first piece of the function: [tex]\( g(x) = x + 4 \)[/tex].
- Substituting [tex]\( x = -4 \)[/tex] into this piece:
[tex]\[ g(-4) = -4 + 4 = 0 \][/tex]
2. Evaluate [tex]\( g(-2) \)[/tex]:
- For [tex]\( x = -2 \)[/tex]:
- Since [tex]\(-5 \leq -2 \leq -1\)[/tex], we use the first piece of the function: [tex]\( g(x) = x + 4 \)[/tex].
- Substituting [tex]\( x = -2 \)[/tex] into this piece:
[tex]\[ g(-2) = -2 + 4 = 2 \][/tex]
3. Evaluate [tex]\( g(0) \)[/tex]:
- For [tex]\( x = 0 \)[/tex]:
- Since [tex]\(-1 < 0 \leq 5\)[/tex], we use the second piece of the function: [tex]\( g(x) = 2 - x \)[/tex].
- Substituting [tex]\( x = 0 \)[/tex] into this piece:
[tex]\[ g(0) = 2 - 0 = 2 \][/tex]
4. Evaluate [tex]\( g(3) \)[/tex]:
- For [tex]\( x = 3 \)[/tex]:
- Since [tex]\(-1 < 3 \leq 5\)[/tex], we use the second piece of the function: [tex]\( g(x) = 2 - x \)[/tex].
- Substituting [tex]\( x = 3 \)[/tex] into this piece:
[tex]\[ g(3) = 2 - 3 = -1 \][/tex]
5. Evaluate [tex]\( g(4) \)[/tex]:
- For [tex]\( x = 4 \)[/tex]:
- Since [tex]\(-1 < 4 \leq 5\)[/tex], we use the second piece of the function: [tex]\( g(x) = 2 - x \)[/tex].
- Substituting [tex]\( x = 4 \)[/tex] into this piece:
[tex]\[ g(4) = 2 - 4 = -2 \][/tex]
So, the results are:
[tex]\[ \begin{array}{l} g(-4) = 0 \\ g(-2) = 2 \\ g(0) = 2 \\ g(3) = -1 \\ g(4) = -2 \end{array} \][/tex]
1. Evaluate [tex]\( g(-4) \)[/tex]:
- For [tex]\( x = -4 \)[/tex]:
- Since [tex]\(-5 \leq -4 \leq -1\)[/tex], we use the first piece of the function: [tex]\( g(x) = x + 4 \)[/tex].
- Substituting [tex]\( x = -4 \)[/tex] into this piece:
[tex]\[ g(-4) = -4 + 4 = 0 \][/tex]
2. Evaluate [tex]\( g(-2) \)[/tex]:
- For [tex]\( x = -2 \)[/tex]:
- Since [tex]\(-5 \leq -2 \leq -1\)[/tex], we use the first piece of the function: [tex]\( g(x) = x + 4 \)[/tex].
- Substituting [tex]\( x = -2 \)[/tex] into this piece:
[tex]\[ g(-2) = -2 + 4 = 2 \][/tex]
3. Evaluate [tex]\( g(0) \)[/tex]:
- For [tex]\( x = 0 \)[/tex]:
- Since [tex]\(-1 < 0 \leq 5\)[/tex], we use the second piece of the function: [tex]\( g(x) = 2 - x \)[/tex].
- Substituting [tex]\( x = 0 \)[/tex] into this piece:
[tex]\[ g(0) = 2 - 0 = 2 \][/tex]
4. Evaluate [tex]\( g(3) \)[/tex]:
- For [tex]\( x = 3 \)[/tex]:
- Since [tex]\(-1 < 3 \leq 5\)[/tex], we use the second piece of the function: [tex]\( g(x) = 2 - x \)[/tex].
- Substituting [tex]\( x = 3 \)[/tex] into this piece:
[tex]\[ g(3) = 2 - 3 = -1 \][/tex]
5. Evaluate [tex]\( g(4) \)[/tex]:
- For [tex]\( x = 4 \)[/tex]:
- Since [tex]\(-1 < 4 \leq 5\)[/tex], we use the second piece of the function: [tex]\( g(x) = 2 - x \)[/tex].
- Substituting [tex]\( x = 4 \)[/tex] into this piece:
[tex]\[ g(4) = 2 - 4 = -2 \][/tex]
So, the results are:
[tex]\[ \begin{array}{l} g(-4) = 0 \\ g(-2) = 2 \\ g(0) = 2 \\ g(3) = -1 \\ g(4) = -2 \end{array} \][/tex]
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