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Which expression is equivalent to [tex]\sin \left(20^{\circ}\right) \cos \left(80^{\circ}\right)-\cos \left(20^{\circ}\right) \sin \left(80^{\circ}\right)[/tex]?

A. [tex]\sin \left(-60^{\circ}\right)[/tex]
B. [tex]\cos \left(-60^{\circ}\right)[/tex]
C. [tex]\cos \left(60^{\circ}\right)[/tex]
D. [tex]\sin \left(60^{\circ}\right)[/tex]


Sagot :

To determine which expression is equivalent to [tex]\(\sin(20^\circ)\cos(80^\circ) - \cos(20^\circ)\sin(80^\circ)\)[/tex], we can use the sine difference formula. The sine difference identity states:

[tex]\[ \sin(A)\cos(B) - \cos(A)\sin(B) = \sin(A - B) \][/tex]

In the given problem, we have:
- [tex]\(A = 20^\circ\)[/tex]
- [tex]\(B = 80^\circ\)[/tex]

Using the sine difference identity, we can rewrite the expression:

[tex]\[ \sin(20^\circ)\cos(80^\circ) - \cos(20^\circ)\sin(80^\circ) = \sin(20^\circ - 80^\circ) \][/tex]

Next, we calculate the angle inside the sine function:

[tex]\[ 20^\circ - 80^\circ = -60^\circ \][/tex]

Thus, the expression simplifies to:

[tex]\[ \sin(20^\circ)\cos(80^\circ) - \cos(20^\circ)\sin(80^\circ) = \sin(-60^\circ) \][/tex]

Therefore, the expression is equivalent to [tex]\(\sin(-60^\circ)\)[/tex].

The correct answer is:
[tex]\[ \sin \left(-60^{\circ}\right) \][/tex]