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Sagot :
To solve the addition of two mixed numbers, let's follow a step-by-step process.
First, we'll convert each mixed number to an improper fraction.
1. Convert [tex]\(-1 \frac{1}{3}\)[/tex] to an improper fraction:
[tex]\[ -1 \frac{1}{3} = -\left(1 + \frac{1}{3}\right) = -\left(\frac{3}{3} + \frac{1}{3}\right) = -\frac{4}{3} \][/tex]
This fraction simplifies to:
[tex]\[ -1 \frac{1}{3} = -1.3333333333333333 \][/tex]
2. Convert [tex]\(-4 \frac{2}{3}\)[/tex] to an improper fraction:
[tex]\[ -4 \frac{2}{3} = -\left(4 + \frac{2}{3}\right) = -\left(\frac{12}{3} + \frac{2}{3}\right) = -\frac{14}{3} \][/tex]
This fraction simplifies to:
[tex]\[ -4 \frac{2}{3} = -4.666666666666667 \][/tex]
Now, add the two improper fractions:
[tex]\[ -1 \frac{1}{3} + \left(-4 \frac{2}{3}\right) = -1.3333333333333333 + (-4.666666666666667) \][/tex]
Combining these, we get:
[tex]\[ -1.3333333333333333 + -4.666666666666667 = -6.0 \][/tex]
Therefore, the sum of [tex]\(-1 \frac{1}{3} + \left(-4 \frac{2}{3}\right)\)[/tex] is:
[tex]\[ -1 \frac{1}{3} + \left(-4 \frac{2}{3}\right) = -6.0 \][/tex]
First, we'll convert each mixed number to an improper fraction.
1. Convert [tex]\(-1 \frac{1}{3}\)[/tex] to an improper fraction:
[tex]\[ -1 \frac{1}{3} = -\left(1 + \frac{1}{3}\right) = -\left(\frac{3}{3} + \frac{1}{3}\right) = -\frac{4}{3} \][/tex]
This fraction simplifies to:
[tex]\[ -1 \frac{1}{3} = -1.3333333333333333 \][/tex]
2. Convert [tex]\(-4 \frac{2}{3}\)[/tex] to an improper fraction:
[tex]\[ -4 \frac{2}{3} = -\left(4 + \frac{2}{3}\right) = -\left(\frac{12}{3} + \frac{2}{3}\right) = -\frac{14}{3} \][/tex]
This fraction simplifies to:
[tex]\[ -4 \frac{2}{3} = -4.666666666666667 \][/tex]
Now, add the two improper fractions:
[tex]\[ -1 \frac{1}{3} + \left(-4 \frac{2}{3}\right) = -1.3333333333333333 + (-4.666666666666667) \][/tex]
Combining these, we get:
[tex]\[ -1.3333333333333333 + -4.666666666666667 = -6.0 \][/tex]
Therefore, the sum of [tex]\(-1 \frac{1}{3} + \left(-4 \frac{2}{3}\right)\)[/tex] is:
[tex]\[ -1 \frac{1}{3} + \left(-4 \frac{2}{3}\right) = -6.0 \][/tex]
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