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Which two elements have the same number of valence electrons?

\begin{tabular}{|c|c|}
\hline Element & Atomic Number \\
\hline barium & 56 \\
\hline neon & 10 \\
\hline silicon & 14 \\
\hline carbon & 6 \\
\hline
\end{tabular}

Sagot :

GinnyAnsweridn
To determine which two elements have the same number of valence electrons, we need to find out the number of valence electrons for each given element.

1. Barium (Atomic Number 56):
- Barium is in the 6th period.
- The valence electrons of elements in the 6th period are found by subtracting 54 from their atomic number.
- Thus, Barium has [tex]\( 56 - 54 = 2 \)[/tex] valence electrons.

2. Neon (Atomic Number 10):
- Neon is in the 2nd period.
- The valence electrons of elements in the 2nd period are found by subtracting 2 from their atomic number.
- Thus, Neon has [tex]\( 10 - 2 = 8 \)[/tex] valence electrons.

3. Silicon (Atomic Number 14):
- Silicon is in the 3rd period.
- The valence electrons of elements in the 3rd period are found by subtracting 10 from their atomic number.
- Thus, Silicon has [tex]\( 14 - 10 = 4 \)[/tex] valence electrons.

4. Carbon (Atomic Number 6):
- Carbon is in the 2nd period.
- The valence electrons of elements in the 2nd period are found by subtracting 2 from their atomic number.
- Thus, Carbon has [tex]\( 6 - 2 = 4 \)[/tex] valence electrons.

Now, we can compare the number of valence electrons for each element:
- Barium: 2 valence electrons
- Neon: 8 valence electrons
- Silicon: 4 valence electrons
- Carbon: 4 valence electrons

The elements that share the same number of valence electrons are Silicon and Carbon, each with 4 valence electrons.

Hence, the correct elements are Silicon and Carbon.
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