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In which triangle is the measure of the unknown angle, [tex]$x$[/tex], equal to the value of [tex]$\sin ^{-1}\left(\frac{5}{8.3}\right)$[/tex]?

Sagot :

To find the measure of the unknown angle, [tex]\( x \)[/tex], in a triangle such that [tex]\( x = \sin^{-1}\left(\frac{5}{8.3}\right) \)[/tex], follow these steps:

1. Compute the ratio:
[tex]\[ \frac{5}{8.3} \approx 0.6024 \][/tex]

2. Calculate the angle in radians:
Using the inverse sine function, find the measure of the angle whose sine is 0.6024.
[tex]\[ x \approx \sin^{-1}(0.6024) \approx 0.6465 \text{ radians} \][/tex]

3. Convert the angle from radians to degrees:
Since angles are often more conveniently expressed in degrees, convert the radians to degrees using the relation [tex]\(1 \text{ radian} = \frac{180}{\pi} \text{ degrees}\)[/tex].
[tex]\[ x \approx 0.6465 \text{ radians} \times \frac{180}{\pi} \approx 37.043 \text{ degrees} \][/tex]

Therefore, in the triangle in question, the measure of the unknown angle [tex]\( x \)[/tex] is approximately [tex]\( 37.043 \)[/tex] degrees.