Discover the best answers to your questions with the help of IDNLearn.com. Join our knowledgeable community to find the answers you need for any topic or issue.

Mustafa's soccer team is planning a school dance as a fundraiser. The DJ charges [tex]$\$[/tex] 200[tex]$ and decorations cost $[/tex]\[tex]$ 100$[/tex]. The team decides to charge each student [tex]$\$[/tex] 5.00[tex]$ to attend the dance. If $[/tex]n[tex]$ represents the number of students attending the dance, which equation can be used to find the number of students needed to make $[/tex]\[tex]$ 1,500$[/tex] in profit?

A. [tex]$5n - 300 = 1,500$[/tex]
B. [tex]$5n + 300 = 1,500$[/tex]
C. [tex]$5n - 200 + 100n = 1,500$[/tex]
D. [tex]$5n - 100 - 200n = 1,500$[/tex]


Sagot :

Let’s break down the problem step by step:

1. Identify the costs involved:
- The DJ's charge is \[tex]$200. - The cost of decorations is \$[/tex]100.
- Therefore, the total cost of the dance is:
[tex]\[ 200 + 100 = \$300 \][/tex]

2. Determine the profit goal:
- The team wants to make a profit of \[tex]$1,500. 3. Charge per student: - Each student is charged \$[/tex]5.00 to attend the dance.

4. Let [tex]\( n \)[/tex] represent the number of students attending the dance.

5. Formulate the equation:
- The income from [tex]\( n \)[/tex] students is [tex]\( 5n \)[/tex] dollars.
- To achieve the desired profit, the income minus the total costs should equal the required profit:
[tex]\[ 5n - 300 = 1500 \][/tex]

6. Check the given options:
- The correct equation fits:
[tex]\[ 5n - 300 = 1500 \][/tex]

This equation accurately represents the situation where:
- [tex]\( 5n \)[/tex] is the total income from students.
- Subtracting the total cost of \[tex]$300 from this income. - The result is the desired profit of \$[/tex]1,500.

Thus, the correct equation to find the number of students needed to make \$1,500 in profit is:
[tex]\[ 5n - 300 = 1500 \][/tex]
Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. IDNLearn.com is your go-to source for accurate answers. Thanks for stopping by, and come back for more helpful information.