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Sagot :
Certainly! Let's walk through the solution of the equation [tex]\(4x = 7(x - 3)\)[/tex] step-by-step, justifying each step.
[tex]\[ \begin{tabular}{|c|c|} \hline \text{Statement} & \text{Reason} \\ \hline 1. \(4x = 7(x - 3)\) & 1. \text{Given equation} \\ \hline 2. \(4x = 7x - 21\) & 2. \text{Distribute 7 to the terms inside the parenthesis} \\ \hline 3. \(4x - 7x = -21\) & 3. \text{Subtract \(7x\) from both sides to isolate \(x\) terms on one side} \\ \hline 4. \(-3x = -21\) & 4. \text{Combine like terms on the left side} \\ \hline 5. \(x = 7\) & 5. \text{Divide both sides by -3 to solve for \(x\)} \\ \hline \end{tabular} \][/tex]
This thorough approach ensures that each step has a clear reason, facilitating understanding of the solution process.
[tex]\[ \begin{tabular}{|c|c|} \hline \text{Statement} & \text{Reason} \\ \hline 1. \(4x = 7(x - 3)\) & 1. \text{Given equation} \\ \hline 2. \(4x = 7x - 21\) & 2. \text{Distribute 7 to the terms inside the parenthesis} \\ \hline 3. \(4x - 7x = -21\) & 3. \text{Subtract \(7x\) from both sides to isolate \(x\) terms on one side} \\ \hline 4. \(-3x = -21\) & 4. \text{Combine like terms on the left side} \\ \hline 5. \(x = 7\) & 5. \text{Divide both sides by -3 to solve for \(x\)} \\ \hline \end{tabular} \][/tex]
This thorough approach ensures that each step has a clear reason, facilitating understanding of the solution process.
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