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Sagot :
To determine how much pressure the block exerts on the tabletop, we need to follow a series of steps.
1. Identify the given values:
- Mass of the block ([tex]\( m \)[/tex]) = 7.5 kg
- Area of the block's bottom surface ([tex]\( A \)[/tex]) = 0.6 m²
- Gravitational acceleration ([tex]\( g \)[/tex]) = 9.8 m/s² (approximated value of gravity)
2. Calculate the force exerted by the block:
The force exerted by the block due to gravity is calculated using the formula:
[tex]\[ F = m \cdot g \][/tex]
Substitute the given values:
[tex]\[ F = 7.5 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 73.5 \, \text{N} \][/tex]
3. Calculate the pressure exerted by the block on the tabletop:
Pressure is defined as the force applied per unit area, and it is calculated using the formula:
[tex]\[ P = \frac{F}{A} \][/tex]
Substitute the values of force and area:
[tex]\[ P = \frac{73.5 \, \text{N}}{0.6 \, \text{m}^2} = 122.5 \, \text{Pa} \][/tex]
Thus, the pressure exerted by the block on the tabletop is 122.5 Pascals.
Therefore, the best answer is:
A. 122.5 Pa
1. Identify the given values:
- Mass of the block ([tex]\( m \)[/tex]) = 7.5 kg
- Area of the block's bottom surface ([tex]\( A \)[/tex]) = 0.6 m²
- Gravitational acceleration ([tex]\( g \)[/tex]) = 9.8 m/s² (approximated value of gravity)
2. Calculate the force exerted by the block:
The force exerted by the block due to gravity is calculated using the formula:
[tex]\[ F = m \cdot g \][/tex]
Substitute the given values:
[tex]\[ F = 7.5 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 73.5 \, \text{N} \][/tex]
3. Calculate the pressure exerted by the block on the tabletop:
Pressure is defined as the force applied per unit area, and it is calculated using the formula:
[tex]\[ P = \frac{F}{A} \][/tex]
Substitute the values of force and area:
[tex]\[ P = \frac{73.5 \, \text{N}}{0.6 \, \text{m}^2} = 122.5 \, \text{Pa} \][/tex]
Thus, the pressure exerted by the block on the tabletop is 122.5 Pascals.
Therefore, the best answer is:
A. 122.5 Pa
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