Get expert advice and insights on any topic with IDNLearn.com. Our experts are ready to provide in-depth answers and practical solutions to any questions you may have.
Sagot :
To determine how much mass is lost through radioactive decay when [tex]\(1.8 \times 10^{15}\)[/tex] joules (J) of energy are released, we can use the famous equation from Einstein's theory of relativity, which relates energy and mass:
[tex]\[ E = mc^2 \][/tex]
Where:
- [tex]\( E \)[/tex] is the energy released.
- [tex]\( m \)[/tex] is the mass lost.
- [tex]\( c \)[/tex] is the speed of light in a vacuum, approximately [tex]\( 3 \times 10^8 \)[/tex] meters per second (m/s).
Rearranging this equation to solve for mass ([tex]\( m \)[/tex]) gives us:
[tex]\[ m = \frac{E}{c^2} \][/tex]
Now, let's substitute the given values into this equation:
1. The energy released [tex]\( E = 1.8 \times 10^{15} \)[/tex] J.
2. The speed of light [tex]\( c = 3 \times 10^8 \)[/tex] m/s.
Substitute these values:
[tex]\[ m = \frac{1.8 \times 10^{15}}{(3 \times 10^8)^2} \][/tex]
Calculate the square of the speed of light:
[tex]\[ (3 \times 10^8)^2 = 9 \times 10^{16} \][/tex]
Now substitute this back into the equation:
[tex]\[ m = \frac{1.8 \times 10^{15}}{9 \times 10^{16}} \][/tex]
Divide the numerator by the denominator:
[tex]\[ m = \frac{1.8}{9} \times 10^{15 - 16} \][/tex]
[tex]\[ m = 0.2 \times 10^{-1} \][/tex]
[tex]\[ m = 0.02 \, \text{kg} \][/tex]
Therefore, the mass lost through radioactive decay when [tex]\( 1.8 \times 10^{15} \)[/tex] J of energy are released is:
A. 0.02 kg
[tex]\[ E = mc^2 \][/tex]
Where:
- [tex]\( E \)[/tex] is the energy released.
- [tex]\( m \)[/tex] is the mass lost.
- [tex]\( c \)[/tex] is the speed of light in a vacuum, approximately [tex]\( 3 \times 10^8 \)[/tex] meters per second (m/s).
Rearranging this equation to solve for mass ([tex]\( m \)[/tex]) gives us:
[tex]\[ m = \frac{E}{c^2} \][/tex]
Now, let's substitute the given values into this equation:
1. The energy released [tex]\( E = 1.8 \times 10^{15} \)[/tex] J.
2. The speed of light [tex]\( c = 3 \times 10^8 \)[/tex] m/s.
Substitute these values:
[tex]\[ m = \frac{1.8 \times 10^{15}}{(3 \times 10^8)^2} \][/tex]
Calculate the square of the speed of light:
[tex]\[ (3 \times 10^8)^2 = 9 \times 10^{16} \][/tex]
Now substitute this back into the equation:
[tex]\[ m = \frac{1.8 \times 10^{15}}{9 \times 10^{16}} \][/tex]
Divide the numerator by the denominator:
[tex]\[ m = \frac{1.8}{9} \times 10^{15 - 16} \][/tex]
[tex]\[ m = 0.2 \times 10^{-1} \][/tex]
[tex]\[ m = 0.02 \, \text{kg} \][/tex]
Therefore, the mass lost through radioactive decay when [tex]\( 1.8 \times 10^{15} \)[/tex] J of energy are released is:
A. 0.02 kg
Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. IDNLearn.com is dedicated to providing accurate answers. Thank you for visiting, and see you next time for more solutions.