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Find the product of [tex]\left(\frac{1}{2} x^3\right)(-10 x)\left(\frac{1}{5} x^2\right)[/tex] and verify the result for [tex]x=1[/tex].

Sagot :

To find the product of [tex]\(\left(\frac{1}{2} x^3\right)(-10 x)\left(\frac{1}{5} x^2\right)\)[/tex] and verify the result for [tex]\(x = 1\)[/tex], follow these steps:

### Step 1: Write down the expression
The given expression is:

[tex]\[ \left(\frac{1}{2} x^3\right)(-10 x)\left(\frac{1}{5} x^2\right) \][/tex]

### Step 2: Multiply the coefficients
First, identify and multiply the numerical coefficients:

- Coefficient of the first term: [tex]\(\frac{1}{2}\)[/tex]
- Coefficient of the second term: [tex]\(-10\)[/tex]
- Coefficient of the third term: [tex]\(\frac{1}{5}\)[/tex]

Multiplying these together:

[tex]\[ \left(\frac{1}{2}\right) \times (-10) \times \left(\frac{1}{5}\right) = \frac{1}{2} \times (-10) \times \frac{1}{5} = -1 \][/tex]

### Step 3: Multiply the [tex]\(x\)[/tex] terms
Now, multiply the [tex]\(x\)[/tex] terms together:

- [tex]\(x^3\)[/tex] from the first term
- [tex]\(x\)[/tex] from the second term
- [tex]\(x^2\)[/tex] from the third term

Combine these exponents (since [tex]\(x^a \times x^b = x^{a+b}\)[/tex]):

[tex]\[ x^3 \times x \times x^2 = x^{3+1+2} = x^6 \][/tex]

### Step 4: Combine coefficients and [tex]\(x\)[/tex] terms
Combining the coefficient and the [tex]\(x\)[/tex] terms, we get:

[tex]\[ -1 \times x^6 = -x^6 \][/tex]

Thus, the product of [tex]\(\left(\frac{1}{2} x^3\right)(-10 x)\left(\frac{1}{5} x^2\right)\)[/tex] simplifies to:

[tex]\[ -\boldsymbol{x^6} \][/tex]

### Step 5: Verify the result for [tex]\(x = 1\)[/tex]
To verify the result for [tex]\(x = 1\)[/tex], substitute [tex]\(x = 1\)[/tex] into the simplified expression [tex]\(-x^6\)[/tex]:

[tex]\[ -x^6 = -1^6 = -1 \][/tex]

Therefore, when [tex]\(x = 1\)[/tex], the expression evaluates to:

[tex]\[ \boldsymbol{-1} \][/tex]

### Summary
Thus, the product of [tex]\(\left(\frac{1}{2} x^3\right)(-10 x)\left(\frac{1}{5} x^2\right)\)[/tex] is [tex]\(-x^6\)[/tex], and when [tex]\(x = 1\)[/tex], the result is [tex]\(-1\)[/tex].
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