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Given: [tex]$K^{\prime}(-8,6)$[/tex] is the image of [tex]$K$[/tex] after a translation along the rule [tex]$(x, y) \rightarrow (x-3, y+6)$[/tex].

What are the coordinates of [tex]$K$[/tex]?


Sagot :

To determine the original coordinates of point [tex]\( K \)[/tex] given its translated image [tex]\( K^{\prime}(-8, 6) \)[/tex] and the translation rule [tex]\((x, y) \rightarrow (x - 3, y + 6)\)[/tex], follow these steps:

1. Understand the translation rule:
- The rule [tex]\((x, y) \rightarrow(x - 3, y + 6)\)[/tex] indicates that for any point [tex]\((x, y)\)[/tex], the x-coordinate is decreased by 3 and the y-coordinate is increased by 6.

2. Set up the relationship using the given translation rule:
- For the image [tex]\( K^{\prime}(x', y') \)[/tex] of a point [tex]\( K(x, y) \)[/tex], the coordinates transformation is:
[tex]\[ x' = x - 3 \quad \text{and} \quad y' = y + 6 \][/tex]

3. Substitute the given coordinates of [tex]\( K^{\prime} \)[/tex] into the transformation equations:
- Given [tex]\( K^{\prime}(-8, 6) \)[/tex]:
[tex]\[ x' = -8 \quad \text{and} \quad y' = 6 \][/tex]

4. Solve for the original coordinates [tex]\( x \)[/tex] and [tex]\( y \)[/tex]:
- Using [tex]\( x' = -8 \)[/tex]:
[tex]\[ -8 = x - 3 \][/tex]
Add 3 to both sides to solve for [tex]\( x \)[/tex]:
[tex]\[ x = -8 + 3 = -5 \][/tex]
- Using [tex]\( y' = 6 \)[/tex]:
[tex]\[ 6 = y + 6 \][/tex]
Subtract 6 from both sides to solve for [tex]\( y \)[/tex]:
[tex]\[ y = 6 - 6 = 0 \][/tex]

5. Combine the results:
- The original coordinates of point [tex]\( K \)[/tex] are:
[tex]\[ K = (-5, 0) \][/tex]

Therefore, the coordinates of [tex]\( K \)[/tex] are [tex]\((-5, 0)\)[/tex].