how do i solve an elimination, substitution, and graphing method for y=25x+35, y=5x+45

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05-06-2014
Mathematics

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how do i solve an elimination, substitution, and graphing method for y=25x+35, y=5x+45

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Tadvisohil886idn Tadvisohil886idn · Answer 1 · 2014-06-05T00:22:49-04:00

Tadvisohil886idn Tadvisohil886idn

05-06-2014

y = 25x + 35
y = 5x + 45

Thus,

25x + 35 = 5x + 45

25x - 5x = 45 - 35

20x = 10

x = 10/20 = 1/2

y = 5x + 45
y = 2.5 + 45
y = 47.5

Thus, x = 1/2, y = 47.5

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Venkatrayaidn Venkatrayaidn · Answer 2 · 2014-06-05T06:34:39-04:00

Venkatrayaidn Venkatrayaidn

05-06-2014

y=25x+35
y=5x+45

25x+35=5x+45

20x=10,x=1/2

y=5 + 45
2
y=47.5

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