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Sagot :
if this is drawn out then the distance and the 9 miles east and 12miles north make a right-angled triangle. We can then use pythagoras' theorem. a^2+b^2=c^2 so 9^2+12^2=hypoteneuse^2
so 81+144=h^2
h^2=225
h=15
so the distance is 15km
so 81+144=h^2
h^2=225
h=15
so the distance is 15km
If the Earth were a flat surface, then 9 miles east and 12 miles north would be
the basis of a right triangle, and the straight-line route would be the hypotenuse.
We could use the Pythagorean Theorem to find the straight-line distance.
A² + B² = C²
C² = (9)² + (12)²
C² = 81 + 144
C² = 225
C = √225 = 15 miles
That's Choice-'H'.
the basis of a right triangle, and the straight-line route would be the hypotenuse.
We could use the Pythagorean Theorem to find the straight-line distance.
A² + B² = C²
C² = (9)² + (12)²
C² = 81 + 144
C² = 225
C = √225 = 15 miles
That's Choice-'H'.
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