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The length of a rectangle is 5 feet more than twice the width. The perimeter is 130 feet. Find the dimensions.

Sagot :

SchwarzschildRadiusidn
So,

The problem tells us that the length of the rectangle is 5 feet more than twice the width.
Mathematically:
length = 5 + 2width
l = 5 + 2w


We know that the perimeter is 2l + 2w.
2l + 2w = 130

2(5 + 2w) + 2w = 130

Distribute
10 + 4w + 2w = 130

Collect Like Terms
10 + 6w = 130

Subtract 10 from both sides
6w = 120

Divide both sides by 6
w = 20

The width is 20.


Since
l = 5 + 2w

Substitute
l = 5 + 2(20)

Multiply
l = 5 + 40

Collect Like Terms
l = 45

The length is 45.

Check
2l + 2w = 130

2(45) + 2(20) = 130

90 + 40 = 130

130 = 130

Width: 20 ft.
Length: 45 ft.
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