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An unknown gas diffuses 0.25 times as fast as He. What is the molecular mass of the unknown gas?

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Dsdrajlinidn

Answer:

64 amu

Explanation:

An unknown gas (X) diffuses 0.25 times as fast as He. Mathematically, we can say that the rate of diffusion of X (rX) is 0.25 that of He.

rX = 0.25 rHe

rX/rHe = 0.25

Given the molecular mass of He (MHe) is 4.00 amu, we can calculate the molecular mass of X using Graham's law of diffusión.

rX/rHe = √(MHe/MX)

0.25 = √(4.00 amu/MX)

MX = 64 amu

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