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A saline solution has 1.9 grams of NaCI in 100 mL of solution. Calculate the molarity

Sagot :

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Answer:  Molality = concentration = 0,33 mol/l

Explanation: Concentration c = n/V   and  n = m/M

M = 55,44 g/mol  and m = 1.9 g , V = 0.100 l

c = m/(MV)

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