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Suppose the galvanic cell sketched below is powered by the following reaction: (s)(aq)(aq)(s) Write a balanced equation for the half-reaction that happens at the cathode of this cell. Write a balanced equation for the half-reaction that happens at the anode of this cell. Of what substance is E1 made? Of what substance is E2 made? What are the chemical species in solution S1? What are the chemical species in solution S2?

Sagot :

Answer:

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answer :

a) Ni²⁺(aq) + 2e⁻ ⇒ Ni(s)

b) Fe(s)  ⇒ Fe²⁺(aq) + 2e⁻

c)  Fe (s)

d) Ni ( s )

e)  Fe²⁺(aq)  and  SO⁻²₄ (aq)

f)  Ni²⁺(aq) and  SO⁻²₄(aq)

Explanation:

a) Balanced equation for the half-reaction at the cathode of the cell

Ni²⁺(aq) + 2e⁻ ⇒ Ni(s)

b) Balanced equation for half reaction at the anode of the cell

Fe(s)  ⇒ Fe²⁺(aq) + 2e⁻

c) E1 is made of  Fe (s)

d) E2 is made of Ni ( s )

e) chemical species in solution S1 = Fe²⁺(aq)  and  SO⁻²₄ (aq)

f) Chemical species in solution S2 = Ni²⁺(aq) and  SO⁻²₄(aq)

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