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a) Ni²⁺(aq) + 2e⁻ ⇒ Ni(s)
b) Fe(s) ⇒ Fe²⁺(aq) + 2e⁻
c) Fe (s)
d) Ni ( s )
e) Fe²⁺(aq) and SO⁻²₄ (aq)
f) Ni²⁺(aq) and SO⁻²₄(aq)
Explanation:
a) Balanced equation for the half-reaction at the cathode of the cell
Ni²⁺(aq) + 2e⁻ ⇒ Ni(s)
b) Balanced equation for half reaction at the anode of the cell
Fe(s) ⇒ Fe²⁺(aq) + 2e⁻
c) E1 is made of Fe (s)
d) E2 is made of Ni ( s )
e) chemical species in solution S1 = Fe²⁺(aq) and SO⁻²₄ (aq)
f) Chemical species in solution S2 = Ni²⁺(aq) and SO⁻²₄(aq)