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If the heat of combustion of hydrogen gas (H) is –285.8 kJ , how many grams of H must combust in order to release
1.2 x 10^3 kJ of heat?
• Your answer should have two significant figures.

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4.2 g of hydrogen is required to release 1.2 x 10^3 kJ of heat.

Given from the question that 1 mole of hydrogen gas contains 2 g of hydrogen gas.

We also know that heat of combustion per mole of hydrogen gas –285.8 kJ.

From the question, we are told that heat released by the reaction is -1.2 x 10^3 kJ of heat.

Hence;

If 2g of hydrogen releases –285.8 kJ of heat

x g of hydrogen releases  -1.2 x 10^3 kJ of heat

x g = 2g  x  -1.2 x 10^3 kJ / –285.8 kJ

xg = 4.2 g of hydrogen

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