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Solve the following system of equations by linear combination:


2d – e = 7

d + e = 5

Sagot :

If you add them straight down:

2d-e = 7
d + e = 5

Then the e's cancel out.  

You are left with 3d = 12

Then solve for d by dividing each side by 3.

Now you have d =4.

To solve for e go back into one of your original equations and substitute 4 for the d.

You can use either equation, so I'll choose the second one.

4 + e = 5
Now solve for e by subtracting each side by 4.

Now you have e = 1.

So your solutions are d = 4 and e = 1
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