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[tex]\text{Given that,}\\\\\text{Width =w}, \\\\\text{Length,}~ l = \dfrac 52 +2w\\\\\text{Perimeter of rectangle}\\\\ =2( l+w)\\\\=2\left(\dfrac 52 + 2w +w\right)\\\\\\=2\left(\dfrac 52 +3w\right)\\\\\\=6w+5~~ \text{units}[/tex]