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The length of a rectangle is 5/2 units greater than twice its width. If its width is w, which expression gives the perimeter of the rectangle in terms of w?
A.
2(5/2w) + w
B.
5/2w + w
C.
3w + 10/2
D.
6w + 5


Sagot :

[tex]\text{Given that,}\\\\\text{Width =w}, \\\\\text{Length,}~ l = \dfrac 52 +2w\\\\\text{Perimeter of rectangle}\\\\ =2( l+w)\\\\=2\left(\dfrac 52 + 2w +w\right)\\\\\\=2\left(\dfrac 52 +3w\right)\\\\\\=6w+5~~ \text{units}[/tex]