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Given ∆ABC with vertices A(−4, −3), B(0, 0), C(2, −3) and ∆DEF with vertices D(3, 1), E(6, -3), F(3, −5), use the definition of congruence in terms of rigid motion to show that ∆ABC ≅ ∆DEF. Describe each rigid motion in terms of coordinates (x, y

Sagot :

By SSS congruency criteria ΔABC ≅ ΔDEF

What is congruency?

Two figures or objects are congruent if they have the same shape and size, or if one has the same shape and size as the mirror image of the other.

The given vertices of the triangles are;

ΔABC: A(−4, −3), B(0, 0), C(2, −3)

ΔDEF:  D(3, 1), E(6, -3), F(3, −5)

The lengths of the sides of ΔABC are

AB = √((0+4)² + (0+3)²) = √25 = 5

BC = √((2-0)² + (-3 - 0)²) = √13  

AC = √((2+4)² + (-3 +3)²) = √36 = 6

The lengths of the sides of ΔDEF are;

DE = √25=5

EF = √13

DF = √36 = 6

As,

AB= DE, BC = EF , AC= DF

So, By SSS congruency criteria ΔABC ≅ ΔDEF

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