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Sagot :
First, we divide the first equation by -6
[tex]\begin{gathered} 6x+6y=-6 \\ -x-y=1 \end{gathered}[/tex]Then, we combine this equation with the second one
[tex]\begin{gathered} 5x-x+y-y=1-13 \\ 4x=-12 \\ x=-\frac{12}{4} \\ x=-3 \end{gathered}[/tex]Now, we use the x-value to find y
[tex]\begin{gathered} 5x+y=-13 \\ 5(-3)+y=-13 \\ -15+y=-13 \\ y=-13+15 \\ y=2 \end{gathered}[/tex]Hence, the solution to the system is (-3, 2).
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