IDNLearn.com provides a user-friendly platform for finding and sharing accurate answers. Join our interactive community and get comprehensive, reliable answers to all your questions.
Sagot :
Q4 . Standard deviation is square root of variance so, the standard deviation of the given data set is , [tex]\sqrt { 42 } [/tex] which is equal to 6.48074069841
Q5.5
To find the standard variation first find the mean of the set.
6+4+9+5+5+4+5 = 38
[tex]\frac { 38 }{ 7 } =5.42[/tex]
Then we will subtract the mean from each number in the set, then will square that. Then we will add those all.
Solution is in the pic. Sorry if this was not explanatory enough.
Ask me if you wanna know more.
Q5.5
To find the standard variation first find the mean of the set.
6+4+9+5+5+4+5 = 38
[tex]\frac { 38 }{ 7 } =5.42[/tex]
Then we will subtract the mean from each number in the set, then will square that. Then we will add those all.
Solution is in the pic. Sorry if this was not explanatory enough.
Ask me if you wanna know more.
Answer:
Step-by-step explanation:
(A) It is given that a data set has a variance of 42, then the standard deviation is given as:
[tex]SD=\sqrt{variance}[/tex]
⇒[tex]SD=\sqrt{42}[/tex]
⇒[tex]SD=6.48[/tex]
Thus, the standard deviation of the given data set is 6.48.
(B) The given data set is:
6 4 9 5 5 4 5
Mean of the given data set is:
[tex]Mean=\frac{6+4+9+5+5+4+5}{7}[/tex]
[tex]Mean=\frac{38}{7}[/tex]
[tex]Mean=5.42[/tex]
Data set [tex](x-\overline{x})^2[/tex]
6 0.33
4 2.01
9 12.81
5 0.17
5 0.17
4 2.01
5 0.17
The variance is given as:
[tex]V=\frac{0.33+2.01+12.81+0.17+0.17+2.01+0.17}{7}[/tex]
[tex]V=2.52[/tex]
Thus, the standard deviation is given as:
[tex]SD=\sqrt{variance}[/tex]
⇒[tex]SD=\sqrt{2.52}[/tex]
⇒[tex]SD=1.6[/tex]
Hence, option A is correct.
We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Thank you for choosing IDNLearn.com. We’re here to provide reliable answers, so please visit us again for more solutions.