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What is the solution to the following inequality?

[tex]\[ \frac{x}{-3} \leq 3 \][/tex]

A. [tex]\( x \geq 1 \)[/tex]
B. [tex]\( x \geq 6 \)[/tex]
C. [tex]\( x \geq -9 \)[/tex]
D. [tex]\( x \leq -9 \)[/tex]


Sagot :

To solve the inequality [tex]\(\frac{x}{-3} \leq 3\)[/tex], follow these steps:

1. Start with the given inequality:
[tex]\[ \frac{x}{-3} \leq 3 \][/tex]

2. Isolate [tex]\(x\)[/tex]. To do this, multiply both sides of the inequality by [tex]\(-3\)[/tex]. Remember, when you multiply or divide both sides of an inequality by a negative number, you must reverse the direction of the inequality sign:
[tex]\[ x \geq 3 \times -3 \][/tex]

3. Simplify the right side of the inequality:
[tex]\[ 3 \times -3 = -9 \][/tex]

4. Thus, the inequality becomes:
[tex]\[ x \geq -9 \][/tex]

So, the correct solution to the inequality [tex]\(\frac{x}{-3} \leq 3\)[/tex] is [tex]\(\boxed{x \geq -9}\)[/tex].

Therefore, the answer is:
C. [tex]\(x \geq -9\)[/tex]
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