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in the given figure, if AB||CD, ∠APQ = 50° and ∠PRD = 130°, then ∠QPR is

In The Given Figure If ABCD APQ 50 And PRD 130 Then QPR Is class=

Sagot :

Answer is 80 degrees

(AB)||(CD)
APQ=PQR= 50 degreed (alternate interior angles)
PRQ=180-PRD=180-130=50 degrees
QPR=180-(PQR-PRQ)
=180-(50+50)
=180-100=80 degrees
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